# The physics of blood pressure drop

by Lys0some
Tags: blood, physics, pressure
 P: 3 Hello everybody. I have seen many people asking questions on this forum about the reason to why blood pressure drops as you get farther from the heart. But honestly, not a single answer satisfied me. My major is physiology, so it's quite funny that I still don't know this "trivial" detail. What is the physics behind the drop in blood pressure? Because I was not satisfied with any of the answers, such as, capillaries have smaller diameters (because diameter shouldn't make a difference in pressure unless you're fitting in the same volume), the blood "losing energy" as it travels across the long resistance journey (because that just doesn't make sense), the arteries are closest to the pump (that's a cool answer, but doesn't explain anything), velocity drops in capillaries (cool, but shouldn't that increase pressure according to Bernoulli's principle? Besides, blood travels faster in veins), because capillaries have higher resistance (well the total cross sectional area of capillaries is actually greater than arteries and greater than veins), etc. So, I decided to come up with my own explanation and I hope someone corrects me if I am wrong. The only way I could make sense out of this is by this reason, imagine a long tube that gets wider in the middle, then back to normal diameter at the end, and a pump at one end of it. When the pump pumps the fluid through, the initial part of the tube is facing a large volume of fluid in front of it that is spread along a long distance, as you proceed through the tube, there is progressively less fluid in front of you. So if we consider the pressure a result of a force at one of the end of the tube and another at the other end, then the weaker the force (impedance) in front of you, the less pressure you would experience. As you have less fluid in front of you, you have less mass to push against a resistant tube, so your pressure drops. The further you move, not only you have less volume of fluid to push, but also less resistance in series, since whatever is left of the tube is getting shorter and shorter. The only issue with this explanation, is that the circulatory system is a closed loop. But again, during diastole, the right atrium pressure is pretty much almost zero (3-8 mmHg), so we can almost assume the tube is open at one end letting with a waterfall of blood pouring in the heart. So can anyone please point out issues in my explanation? Thanks
P: 560
 Quote by Lys0some Hello everybody. I have seen many people asking questions on this forum about the reason to why blood pressure drops as you get farther from the heart. But honestly, not a single answer satisfied me. My major is physiology, so it's quite funny that I still don't know this "trivial" detail. What is the physics behind the drop in blood pressure? Because I was not satisfied with any of the answers, such as, capillaries have smaller diameters (because diameter shouldn't make a difference in pressure unless you're fitting in the same volume), the blood "losing energy" as it travels across the long resistance journey (because that just doesn't make sense), the arteries are closest to the pump (that's a cool answer, but doesn't explain anything), velocity drops in capillaries (cool, but shouldn't that increase pressure according to Bernoulli's principle? Besides, blood travels faster in veins), because capillaries have higher resistance (well the total cross sectional area of capillaries is actually greater than arteries and greater than veins), etc. So, I decided to come up with my own explanation and I hope someone corrects me if I am wrong. The only way I could make sense out of this is by this reason, imagine a long tube that gets wider in the middle, then back to normal diameter at the end, and a pump at one end of it. When the pump pumps the fluid through, the initial part of the tube is facing a large volume of fluid in front of it that is spread along a long distance, as you proceed through the tube, there is progressively less fluid in front of you. So if we consider the pressure a result of a force at one of the end of the tube and another at the other end, then the weaker the force (impedance) in front of you, the less pressure you would experience. As you have less fluid in front of you, you have less mass to push against a resistant tube, so your pressure drops. The further you move, not only you have less volume of fluid to push, but also less resistance in series, since whatever is left of the tube is getting shorter and shorter. The only issue with this explanation, is that the circulatory system is a closed loop. But again, during diastole, the right atrium pressure is pretty much almost zero (3-8 mmHg), so we can almost assume the tube is open at one end letting with a waterfall of blood pouring in the heart. So can anyone please point out issues in my explanation? Thanks
I'm almost certain the answer is friction, and speculating isn't really kosher on these forums.

http://faculty.weber.edu/nokazaki/Hu...20pressure.ppt
P: 3
 Quote by Student100 I'm almost certain the answer is friction, and speculating isn't really kosher on these forums. http://faculty.weber.edu/nokazaki/Hu...20pressure.ppt
Well can you explain how friction reduces blood pressure? I mean, axial friction can only slow down the blood, which would locally increase blood pressure. Blood velocity is slower in the capillaries than the arteries, yet the pressure is lower. Blood velocity is faster in the veins than capillaries, yet blood pressure is lower. So velocity is not the main determinant of blood pressure. Total cross-sectional area is highest in capillaries, but blood pressure decreases progressively, so that is not the cause either. Total resistance is likely low in the capillaries, because they add in parallel.

And I am not speculating, I am making an educated guess. As if the rest of the answers make sense anyway.

 P: 288 The physics of blood pressure drop The basics of pressure losses are explained by simple fluid dynamics. It is a shame that they did not go into it in at least some detail during your studies. Let's first ignore all the difficult things (non-Newtonian flow, flexible walls, etc) and consider the flow through a simple pipe with solid walls. The Bernoulli equation states that the total pressure is constant only when there are no frictional losses. If there is viscosity, you will have pressure losses. The total pressure will go down. if the pipe diameter stays constant, velocity will not change (because of conservation of momentum) and therefore the static pressure will go down. In the simplest case, laminar flow, the pressure loss is given by: $\Delta P = \frac{64}{Re}\frac{L}{D}\frac{1}{2}\rho V^2$ with D=diameter of pipe L=length of pipe $\rho$=density V=velocity Re=Reynolds number $Re=\frac{\rho V L}{\mu}$ (the derivation of the pressure loss equation is in most basic thermodynamics textbooks, e.g. Cengel - thermodynamics) The internal energy goes down because static pressure goes down. The pressure loss is per unit length of pipe, so the more distance you travel, the lower the total pressure and the more internal energy you have lost (to friction at the walls, which is converted in the end to heat.). If the diameter is smaller, the pressure loss is larger per unit length, so you lose more per meter in the capillaries than in the arteries. Note that blood flow is actually quite special. In the capillaries, the blood cells are larger than the diameter of the capillaries, and you cannot speak about continuum fluid dynamics anymore, so Bernoulli's equation is not valid.