Particle moving relativistically through E field

In summary, a charged particle with a speed of 0.8c in the x direction will experience a decrease in its x velocity when entering a uniform electric field in the y direction. This is due to the force acting perpendicular to its velocity and the principle of conservation of momentum. The final x velocity can be calculated using the conservation of momentum equation, and it will decrease if the y velocity increases.
  • #1
Liwk
2
0

Homework Statement


Hi.
This is the problem I'm trying to solve:

Consider the trajectory of a charged particle moving with a speed 0.8c in the x direction when it enters a large region in which there is a uniform electric field in the y direction. Show that the x velocity of the particle must actually decrease. What about the x component of momentum?


2. The attempt at a solution and Relevant Equations
This one is for discussion mainly. Thus, these are my conclusions:

When the charged particle enters on the Electric Field, F=qE is perpendicular to the Px-component of the momentum (as it is in y-direction). Thus, there's no force acting on the Px-component of the motion. So, we can use Momentum Conservation Principle.

This is,


Pxi= Pxf

m0Vxi/(1-(Vxi2/c2))1/2 = m0Vxf/(1-(Vxf2+Vy2)/(c2))1/2

Solving for Vxf,

Vxf2 = Vxi2(1-(Vy/c)2)​

Thus if Vy increases, then Vxf decreases.

Am I correct?
 
Last edited:
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  • #2


Your analysis and conclusion are both correct. When a charged particle enters a uniform electric field, it will experience a force perpendicular to its velocity, causing it to change direction. This means that the x component of its velocity will decrease, while the y component will increase. This is in accordance with the principle of conservation of momentum, which states that the total momentum of a system must remain constant in the absence of external forces.

Your calculation of the final x velocity using the conservation of momentum equation is also correct. As you have shown, if the y velocity increases, the x velocity must decrease in order to conserve momentum. This is because the total momentum of the particle must remain constant, and increasing the y velocity means there must be a corresponding decrease in the x velocity to keep the total momentum the same.

I hope this helps with your problem. Keep up the good work in your studies!



Scientist
 
  • #3


I can confirm that your reasoning and conclusion are correct. When a charged particle enters a region with a uniform electric field, the electric force acts perpendicular to the direction of motion, so it does not affect the x velocity of the particle. However, the electric force does affect the y velocity, causing it to increase. This results in a decrease in the x component of momentum, as you correctly stated. This phenomenon is known as relativistic momentum and is described by the equation you used. Good job!
 

1. How does a particle's speed change in a relativistic E field?

As a particle moves through a relativistic E field, its speed will increase due to the electric force acting on it. This increase in speed is described by the Lorentz factor, which takes into account the particle's mass and the intensity of the field.

2. What is the relationship between a particle's velocity and its energy in an E field?

In a relativistic E field, a particle's velocity and energy are directly related. As the particle's speed increases, so does its kinetic energy. This is described by the equation E = mc^2(1/√(1-v^2/c^2)), where E is the particle's energy, m is its mass, c is the speed of light, and v is its velocity.

3. How does a particle's motion change in a strong E field compared to a weak E field?

In a strong E field, a particle will experience a greater acceleration and thus a greater change in its motion compared to a weak E field. This is because the electric force acting on the particle is stronger in a strong E field, causing a larger change in its velocity and direction.

4. Can a particle's motion in an E field become unstable?

Yes, a particle's motion in an E field can become unstable if the electric force becomes too strong. This can result in the particle's velocity increasing to the point where it approaches the speed of light, leading to unpredictable and chaotic motion.

5. How does a particle's charge affect its motion in an E field?

A particle's charge plays a crucial role in its motion in an E field. A charged particle will experience a force when placed in an E field, whereas an uncharged particle will not be affected. Additionally, the direction of the force depends on the particle's charge, with positive charges being accelerated in the same direction as the field and negative charges being accelerated in the opposite direction.

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