Let a and b denote 2 2d vectors

  • Thread starter ibaforsale
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    2d Vectors
In summary: Hint: If ##a \le b## then ##a^2 \le b^2##In summary, the conversation involved solving a problem in which the goal was to show that a dot product of two 2D vectors, a and b, is less than or equal to the product of their magnitudes. The conversation walked through finding the dot product and magnitude of a and b, and then manipulating the inequality to prove its truth. The final step involved using the property that if a is less than or equal to b, then a squared is also less than or equal to b squared.
  • #36
First, the things you are squaring aren't the same as the things you are multiplying by two, and secondly, (1/2)2 < 2*(1/2) so the basic logic there doesn't work.

You need to do some algebra to re-write the right hand side.
 
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  • #37
Squaring ##1## isn't bigger than multiplying it by ##2##. Look, you need to do some algebraic manipulation with that expression to make it obvious that is is ##\ge 0##. We have led you by the hand to this point and I don't see how we can give you that last step without having worked the whole problem for you.

As a matter of curiosity, what course are you in and what courses have you already had?
 
  • #38
i was thinking the algebra might include taking out common terms but there are none, can i get a hint as to what needs to happen
 
  • #39
LCKurtz said:
We have led you by the hand to this point and I don't see how we can give you that last step without having worked the whole problem for you.
That's how I feel as well.
 

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