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Effect on current, if a higher voltage is applied |
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| Dec31-12, 12:45 PM | #1 |
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Effect on current, if a higher voltage is applied
I'm confused over this because generally i'm told that if the voltage increases then so does current and this satisfies the equation:V=IR because I=V/R increasing the top of the fraction should mean that the current increases but this contradicts the equation:P=IV be=P/cause this time I=P/V and if you increase the voltage then the current should go down as is the rule with the bottom of the fraction.These two equations just don't make sense with each other-one equation says that increasing the voltage increases the current and the other says that increasing the voltage decreases the current.
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| Dec31-12, 01:06 PM | #2 |
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If you increase the voltage across a resistor, then both the current and power increase. V=IR and P=VI. |
| Dec31-12, 01:09 PM | #3 |
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Recognitions:
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| Dec31-12, 01:12 PM | #4 |
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Mentor
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Effect on current, if a higher voltage is applied
As one concrete example, consider a high-efficiency DC-DC converter. The output voltage is fixed, and the output current through a resistor would be fairly constant. So the power drawn from the input terminals in this situation is pretty much a constant power Pin.
Now, as you raise the input voltage Vin, the input current Iin drops. It's a very common characteristic for DC-DC converters, |
| Dec31-12, 01:20 PM | #5 |
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| Dec31-12, 04:30 PM | #6 |
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In most but not all circuits if you increase V then both I and P will also increase. For a resistive circuit: I = V/R and P = V2/R By inspection it's clear that if you change V then P increases faster than I. |
| Dec31-12, 06:39 PM | #7 |
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