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Is there any equivalent for Ln(1+ax)? |
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| Jan28-13, 04:03 AM | #1 |
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Is there any equivalent for Ln(1+ax)?
Hello friends,
I would like to know the equivalent expression/function for Ln(1+ax), where 'a' is constant. I am not interested in series expansion, I would like to know whether it can be written in terms of sum of other simple terms/functions ( It can be trigonometric, hyperbolic, etc.,) Thank you |
| Jan28-13, 09:51 AM | #2 |
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Mentor
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There are different ways to write ln(1+ax), but they are all more complicated.
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| Jan28-13, 11:25 AM | #3 |
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This is a pretty ambiguous question. There are many ways to write an equivalency. Without knowing more specifically what you are trying to do, it would be hard to give you an answer that would work for you.
alternatively, you can explore wolfram and see where that takes you I suppose. |
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