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Equation to graph a 180 degree curve comprised of a radius and an ellipse |
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| Nov30-12, 02:30 PM | #1 |
| Nov30-12, 03:46 PM | #2 |
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Mentor
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Some helpful equations: An ellipse aligned with the coordinate axes can be expressed as ##\frac{x^2}{a^2}+\frac{y^2}{b^2}=1## or ##y(x)=\pm b \sqrt{1-\frac{x^2}{b^2}}## Curve radius is given by $$R = \frac{(1+y'^2)^{\frac{3}{2}}}{y''}$$ where ' is the derivative with respect to x. The curve radius of a circle is the regular radius of the circle, of course. 45° away from the intersections of the major axes and the ellipse are points with y'=±1. This simplifies curvature to ##R=\frac{\sqrt{8}}{y''}##, but it applies to a special case of your construction only. |
| Nov30-12, 04:09 PM | #3 |
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Thanks, you are right, I should have included that. I will add it, and drawing to my original question/post. The end of the ellipse portion (at the end of the 180 degree curve) would correspond to the middle of the major axis (where the ellipse intersects line B on the drawing, above). Thanks. |
| Dec1-12, 09:28 AM | #4 |
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Equation to graph a 180 degree curve comprised of a radius and an ellipse
(below)
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| Dec1-12, 12:57 PM | #5 |
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If you know a and b and the 45°-part of the ellipse is like in the sketch, with the origin of the coordinate system in its center: Derive y and solve for y'=-1 (it has a nice general solution) to find the corresponding x-value of point P where ellipse and circle meet. Use this x-value in y(x) to get the corresponding y-value for P. Use some tool of your choice to draw y(x) between the calculated x-value and x=a. Derive y' to get y'', insert your calculated x-value and plug that in the formula for the curve radius to get the curve radius R. The center of your circle is now ##\frac{R}{\sqrt{2}}## to the left and below P. Its center is M(c,d) and the circle equation is ##(x-c)^2 + (y-d)^2 = R^2## or ##y(x)=d+\sqrt{R^2-(x-c)^2}##. Draw this for x=c-R to point P. |
| Dec1-12, 02:14 PM | #6 |
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I'm probably misunderstanding you, but, from P to the center of the circular portion (as opposed to the ellipse portion) should just be R (the radius), not R / sqr 2. Correct? |
| Dec2-12, 07:48 AM | #7 |
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The total distance is R, but it is composed of the distance in x- and y-direction, which have the same magnitude.
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| Dec2-12, 08:59 AM | #8 |
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Can anyone make a drawing or a graph of this, please?
I know this is a math forum, and I do appreciate math, but I am not very good at it. That's why I am here. I don't know how to "derive" things, so I need a more basic explanation. Pretend I'm an average high school freshman and you'd probably be pretty close to my level of understanding. I get that R / sqr 2 = the length of the x and y paths from P to M, now. Thanks |
| Dec3-12, 12:06 PM | #9 |
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Anyone?
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| curvature, ellipse, equation, graph, radius |
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