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ahhppull
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Homework Statement
A 200.0 mL buffer solution is 0.280 M in acetic acid and 0.280 M in sodium acetate. What is the pH after addition of 0.0050 mol of HCl?
Homework Equations
pH = pKa + log[base]/[acid]
The Attempt at a Solution
I have a problem with the significant figures. The website won't accept my answer. Or maybe I'm just wrong.
The initial ph is 4.74 and when HCl is added, the concentration of sodium acetate decreases by .0050 and the concentration of acetic acid increases by .0050
Therefore the equation becomes pH = 4.74 + log [.275]/[.285]
My answers I have inputted were 4.72 and 4.73