Henderson-Hasselbalch equation

  • Thread starter ahhppull
  • Start date
In summary, a 200.0 mL buffer solution with a concentration of 0.280 M in acetic acid and 0.280 M in sodium acetate has a pH of 4.74. After adding 0.0050 mol of HCl, the concentration of sodium acetate decreases by 0.0050 mol and the concentration of acetic acid increases by 0.0050 mol. The revised equation for pH is pH = 4.74 + log [.051]/[.061], resulting in a final pH of 4.67. The reason for the discrepancy in the answer was due to an error in the calculation, which was later corrected.
  • #1
ahhppull
62
0

Homework Statement



A 200.0 mL buffer solution is 0.280 M in acetic acid and 0.280 M in sodium acetate. What is the pH after addition of 0.0050 mol of HCl?

Homework Equations



pH = pKa + log[base]/[acid]

The Attempt at a Solution



I have a problem with the significant figures. The website won't accept my answer. Or maybe I'm just wrong.

The initial ph is 4.74 and when HCl is added, the concentration of sodium acetate decreases by .0050 and the concentration of acetic acid increases by .0050

Therefore the equation becomes pH = 4.74 + log [.275]/[.285]

My answers I have inputted were 4.72 and 4.73
 
Physics news on Phys.org
  • #2
Nvm, no help needed. I figured out what the problem is.
 
  • #3
Would be nice if you can tell what it was.
 
  • #4
Oh, I did the problem wrong. The right was to do it was:

.28 M acetic acid x .200 L = .056 moles acetic acid
.056 moles acetic acid + .005 moles (from HCl) = .061 moles acetic acid

.28 M sodium acetate x .200 L = .056 moles sodium acetate
.056 moles sodium acetate - .005 moles = .051 moles sodium acetate

pH = 4.74 + log [.051]/[.061]
pH = 4.67
 
  • #5
, but the website says they are incorrect.

The Henderson-Hasselbalch equation is a fundamental equation in acid-base chemistry that is used to calculate the pH of a buffer solution. It relates the concentrations of a weak acid and its conjugate base to the pH of the solution. In this case, the equation can be used to calculate the pH of the buffer solution before and after the addition of HCl.

Based on the given information, the initial pH of the buffer solution is 4.74. After the addition of 0.0050 mol of HCl, the concentration of acetic acid increases to 0.285 M and the concentration of sodium acetate decreases to 0.275 M. Plugging these values into the Henderson-Hasselbalch equation, we get:

pH = 4.74 + log[0.275]/[0.285] = 4.74 + log[0.9649] = 4.74 - 0.015 = 4.725

The pH after the addition of HCl is therefore 4.725. This answer is within the acceptable range of significant figures, so it should be accepted by the website. If not, it is possible that there is a rounding error or a mistake in the calculations. Overall, the Henderson-Hasselbalch equation is a useful tool for understanding and predicting the behavior of buffer solutions in acid-base chemistry.
 

What is the Henderson-Hasselbalch equation?

The Henderson-Hasselbalch equation is a mathematical formula used to calculate the pH of a solution containing a weak acid and its conjugate base. It takes into account the concentration of the acid and its dissociation constant.

How is the Henderson-Hasselbalch equation derived?

The equation is derived from the acid dissociation constant (Ka) and the law of mass action. It assumes that the concentration of the acid and its conjugate base are in equilibrium, and that the solution is in a state of buffering.

What is the significance of the Henderson-Hasselbalch equation in biochemistry?

The Henderson-Hasselbalch equation is commonly used in biochemistry to determine the pH of a solution containing a weak acid and its conjugate base, such as blood. It is also used to understand the relationship between pH, pKa, and the ratio of acid to base in a solution.

What is the pKa value in the Henderson-Hasselbalch equation?

The pKa value is the negative logarithm of the acid dissociation constant (Ka). It is a measure of the strength of an acid, with lower pKa values indicating a stronger acid and higher pKa values indicating a weaker acid.

What are some limitations of the Henderson-Hasselbalch equation?

The Henderson-Hasselbalch equation assumes that the acid and its conjugate base are in equilibrium and that the solution is in a state of buffering. It also does not take into account the influence of other ions or molecules in the solution. Additionally, it is only applicable to weak acids and their conjugate bases.

Similar threads

  • Chemistry
Replies
8
Views
948
  • Biology and Chemistry Homework Help
Replies
3
Views
1K
  • Biology and Chemistry Homework Help
Replies
7
Views
2K
  • Biology and Chemistry Homework Help
Replies
4
Views
1K
  • Biology and Chemistry Homework Help
Replies
2
Views
2K
  • Biology and Chemistry Homework Help
Replies
1
Views
1K
Replies
8
Views
866
  • Biology and Chemistry Homework Help
Replies
1
Views
3K
  • Biology and Chemistry Homework Help
Replies
23
Views
2K
  • Biology and Chemistry Homework Help
Replies
11
Views
2K
Back
Top