- #36
DDS
- 171
- 0
can anyone help me from here?
DDS said:These are the derivatives i get:
wKA^2cos(2wt)
or
tKA^2cos(2wt)
i am leaning toward the first one...AM i right?>?>
To get a meaningful answer, use a single value for t. (For some reason, you used both values for t in the same expression.)DDS said:the times which i plugged in and are correct are as follows:
0.212s and 1.06 s
this is what i have done thus far:
A=0.0455 m
K=3.76 N/m
w=3.70
(3.76)*(0.0455)^2*(3.70)cos(3.70)(0.212)*sin(3.70)(1.06)
7.78414e-3[3.699653267][0.068398368]
=1.953e-3
Incorrect. Realize that [itex]\omega[/itex] = 3.7 radians/sec, not degrees/sec.DDS said:okay my times expressed the way you suggested are:
0.212
cos(3.70)(0.212)=0.9999
sin(3.70)(0.212)=0.13689
now as i mentioned time and time again...here is where i am stuck. i do not know which time or time to plug into my full d(KE)/dt expression
Right! The value of d(KE)/dt is exactly the same for both times.DDS said:so if i did this correctly both times seem to be similar so either i did it wrong or it doesn't matter which time you choose