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sozener1
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how do I find the derivative of tanh^-1(sinh(2x))
do I just find derivative of tanh^-1(x) this then substitute sinh(2x) into x??
do I just find derivative of tanh^-1(x) this then substitute sinh(2x) into x??
sozener1 said:how do I find the derivative of tanh^-1(sinh(2x))
do I just find derivative of tanh^-1(x) this then substitute sinh(2x) into x??
The formula for finding the derivative of tanh-1(x) is 1/(1-x2).
The chain rule is used to find the derivative of tanh-1(x) because it is a composite function of tanh(x) and its inverse function.
You can simplify the derivative of tanh-1(x) by using the identity tanh-1(x) = (ln(1+x) - ln(1-x))/2.
The derivative of tanh-1(x) exists for all values of x except for -1 and 1.
Yes, the derivative of tanh-1(x) can be negative. It depends on the value of x and the interval in which it lies.