How to find derivative of tanh^-1(x)

  • Thread starter sozener1
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In summary, to find the derivative of tanh^-1(sinh(2x)), you must apply the Chain Rule and also remember to calculate the inner derivative. This can also be rewritten and simplified as 2cosh 2x over 1 - sinh^2 2x.
  • #1
sozener1
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how do I find the derivative of tanh^-1(sinh(2x))

do I just find derivative of tanh^-1(x) this then substitute sinh(2x) into x??
 
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  • #2
sozener1 said:
how do I find the derivative of tanh^-1(sinh(2x))

do I just find derivative of tanh^-1(x) this then substitute sinh(2x) into x??

Yes, but since the Chain Rule applies here, you must not forget the inner derivative.

It is also possible that this can be rewritten and simplified, but I'm too tired to figure this out now...
 
  • #3
Chain Rule, Chain Rule, Chain Rule!
[itex] \frac{d}{dx} (\tanh^{-1} \sinh 2x) = \frac{d}{dx} (\tanh^{-1} \sinh 2x) \cdot \frac{d}{dx} \sinh 2x = \frac{1}{1 - \sinh^2 2x} \cdot 2\cosh2x [/itex]
Thus,
[itex] \frac{d}{dx} (\tanh^{-1} \sinh 2x) = \frac{2 \cosh 2x}{1 - \sinh^2 2x} [/itex]
 

What is the formula for finding the derivative of tanh-1(x)?

The formula for finding the derivative of tanh-1(x) is 1/(1-x2).

What is the chain rule used for when finding the derivative of tanh-1(x)?

The chain rule is used to find the derivative of tanh-1(x) because it is a composite function of tanh(x) and its inverse function.

How do you simplify the derivative of tanh-1(x)?

You can simplify the derivative of tanh-1(x) by using the identity tanh-1(x) = (ln(1+x) - ln(1-x))/2.

What are the possible values of x for which the derivative of tanh-1(x) exists?

The derivative of tanh-1(x) exists for all values of x except for -1 and 1.

Can the derivative of tanh-1(x) be negative?

Yes, the derivative of tanh-1(x) can be negative. It depends on the value of x and the interval in which it lies.

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