- #1
punjabi_monster
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Here is a question I am having trouble with :uhh: , thanks for your help.
Electrons are ejected from a photoelectric surface with a maximum speed of 4.20 * 10^5 m/s. If the work function of this surface is 2.55 eV, what is the wavelength of the incident light?
This is how i tried to solve this question:
Ek=(1/2)mv^2
Ek=(1/2)(9.11*10^-31 kg)(4.20*10^5 m/s)^2
Ek=8.04*10^-20 J
E=hc/λ
λ=[(6.63*10^-34 Js)(3.00*10^8 m/s)]/(8.04*10^-20 J)
λ=(2.48*10^-6 m) :yuck:
The actual answer is (4.07*10^-7 m).
Can you please tell me the correct way to do this question. Thanks.
Electrons are ejected from a photoelectric surface with a maximum speed of 4.20 * 10^5 m/s. If the work function of this surface is 2.55 eV, what is the wavelength of the incident light?
This is how i tried to solve this question:
Ek=(1/2)mv^2
Ek=(1/2)(9.11*10^-31 kg)(4.20*10^5 m/s)^2
Ek=8.04*10^-20 J
E=hc/λ
λ=[(6.63*10^-34 Js)(3.00*10^8 m/s)]/(8.04*10^-20 J)
λ=(2.48*10^-6 m) :yuck:
The actual answer is (4.07*10^-7 m).
Can you please tell me the correct way to do this question. Thanks.
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