Derive conservation of center of mass position

In summary: Where V_CoM is the velocity of the center of mass. In summary, the conservation of center of mass position ensures that the boat will shift a small distance in the opposite direction when the mass m is moved from one end to the other end, as shown by the formula $\frac{x_1\,m+x_2\,M}{m+M} = \frac{\tilde{x_1}\,m+\tilde{x_2}\,M}{m+M}$ derived from conservation of momentum.
  • #1
Jonsson
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Hello there,

If a mass, m, is placed at one end of an boat of mass M, which is located on a frictionless ocean. If the mass, m, is moved from one end of the boat to the other end, conservation of center of mass position ensures that the boat shifts a small distance in the opposite direction. The conservation of mass is given by: $$\frac{x_1\,m+x_2\,M}{m+M} = \frac{\tilde{x_1}\,m+\tilde{x_2}\,M}{m+M}$$ where each x equal the position of the masses.

How can I derive this forumla from more fundamental physics?

Thank you for your time,

Kind regards,
Marius

PS: how can I most easily do inline latex? Is it possible to do something similar to $expr$? Thanks
 
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  • #2
This has to do with conservation of momentum. You can show that for the system as a whole to have 0 momentum throughout the motion of the mass m, the center of mass position must not move. This assumes that the external forces are 0 and so by Newton's second law dp/dt=0, and in a frame where p(t=0)=0, dp/dt=0 for all t implies p(t)=0 for all t.

In the above, p stands for the momentum of the entire object (m+M). From this it can be derived that the CoM position must not move because p=(m+M)V_CoM.
 
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1. What is the center of mass position?

The center of mass position is the point at which the total mass of an object is considered to be concentrated, and the object can be balanced perfectly on that point.

2. How is the center of mass position calculated?

The center of mass position is calculated by finding the weighted average of the positions of all the individual particles that make up an object. This is done by multiplying the mass of each particle by its distance from a chosen reference point, then dividing the sum of these values by the total mass of the object.

3. Why is the conservation of center of mass position important?

The conservation of center of mass position is important because it is a fundamental principle in physics that states that the total momentum of a system remains constant, as long as no external forces act upon it. This allows us to make predictions about the behavior of objects and systems in motion.

4. How does the conservation of center of mass position apply to real-world situations?

The conservation of center of mass position applies to many real-world situations, such as the motion of objects in space, the motion of vehicles, and even the motion of people. It allows us to understand and predict the behavior of these objects and systems, and is essential in fields such as rocket science and biomechanics.

5. Are there any exceptions to the conservation of center of mass position?

In isolated systems, the conservation of center of mass position holds true. However, in systems where external forces are present, such as in collisions, there may be temporary changes in the center of mass position. Overall, however, the total momentum and center of mass position will remain constant.

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