- #1
end3r7
- 171
- 0
It's a volterra equation with a continuous delay
*I is negative infinity, couldn't figure out how to write it
[tex]
\dot{x} = rx(t)[1 - K^-1\int_{I}^{t} k(t-s)x(s)\,ds]
[/tex]
The part in parenthesis is the density dependent factor, but I don't understand how the integral works exactly. I know the function k(t) is a weightfactor which says how much weight should be given to past populations.
So let's see if I get it, feel free to yell at me (AKA reply in CAPS) if I am wrong.
k(t-s)x(s) is same as the function k(t) shifted to the right by s multiplied by a scalar (here x(s) represents a population at time t=s).
Thus the integral is just going to be the summation of all these functions from initial up to current time. This is going to be a function in 't'.
If the max of the kernel occurs at zero then there is almost no delay, right?
Cuz it follows that, say, k(t-s)x(s) will contribute the most to the resulting integral when s=t=now.
On the other hand, if max is at t=T then the major contributor will be when t-s = T, or s = t-T, that is, T generations ago.
If anybody wants to add/correct anything, feel more than free. =)
*I is negative infinity, couldn't figure out how to write it
[tex]
\dot{x} = rx(t)[1 - K^-1\int_{I}^{t} k(t-s)x(s)\,ds]
[/tex]
The part in parenthesis is the density dependent factor, but I don't understand how the integral works exactly. I know the function k(t) is a weightfactor which says how much weight should be given to past populations.
So let's see if I get it, feel free to yell at me (AKA reply in CAPS) if I am wrong.
k(t-s)x(s) is same as the function k(t) shifted to the right by s multiplied by a scalar (here x(s) represents a population at time t=s).
Thus the integral is just going to be the summation of all these functions from initial up to current time. This is going to be a function in 't'.
If the max of the kernel occurs at zero then there is almost no delay, right?
Cuz it follows that, say, k(t-s)x(s) will contribute the most to the resulting integral when s=t=now.
On the other hand, if max is at t=T then the major contributor will be when t-s = T, or s = t-T, that is, T generations ago.
If anybody wants to add/correct anything, feel more than free. =)