Projectile Motion Ball Problem help

In summary, compressed air is used to propel a ball upwards from a -m-tall tube, with the air exerting an upward force on the ball as long as it is in the tube. The question is asking for the height that the ball reaches above the top of the tube.
  • #1
Nanofan01
5
0
Compressed air is used to fire a ball vertically upward from a -m-tall tube. The air exerts an upward force of on the ball as long as it is in the tube.

How high does the ball go above the top of the tube?
 
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  • #2
Hi Nanofan01, welcome to PF. Please observe the rules that ask you to use the homework template and fill in the relevant equations and your thoughts on the problem.

NOTE: You MUST show that you have attempted to answer your question in order to receive help. You MUST make use of the homework template, which automatically appears when a new topic is created in the homework help forums.
 
  • #3


To calculate the height reached by the ball, we need to use the equations of motion for projectile motion. The initial velocity of the ball is zero, since it is fired from rest. The acceleration due to gravity is always acting downward and is equal to 9.8 m/s^2. The force exerted by the compressed air on the ball is equal to its mass multiplied by the acceleration due to gravity.

Using the equation h = u^2/2g, where h is the maximum height, u is the initial velocity, and g is the acceleration due to gravity, we can calculate the height reached by the ball. In this case, u = 0, so the equation simplifies to h = 0. We can conclude that the ball does not go above the top of the tube.

However, if there is a certain amount of air resistance acting on the ball, the initial velocity will not be zero and the ball will reach a certain height above the top of the tube before falling back down. In this case, we would need to use more advanced equations of motion to calculate the exact height reached by the ball.
 

1. How do I calculate the initial velocity of a projectile?

The initial velocity of a projectile can be calculated using the formula: v = d/t, where v is the velocity, d is the displacement, and t is the time. Alternatively, you can also use the formula: v = u + at, where u is the initial velocity, a is the acceleration, and t is the time.

2. How do I calculate the maximum height of a projectile?

The maximum height of a projectile can be calculated using the formula: h = (v^2 * sin^2(theta))/2g, where h is the maximum height, v is the initial velocity, theta is the angle of projection, and g is the acceleration due to gravity (9.8 m/s^2).

3. How do I calculate the time of flight for a projectile?

The time of flight for a projectile can be calculated using the formula: t = (2v * sin(theta))/g, where t is the time of flight, v is the initial velocity, theta is the angle of projection, and g is the acceleration due to gravity (9.8 m/s^2).

4. How do I find the range of a projectile?

The range of a projectile can be calculated using the formula: R = (v^2 * sin(2theta))/g, where R is the range, v is the initial velocity, theta is the angle of projection, and g is the acceleration due to gravity (9.8 m/s^2).

5. What is the difference between projectile motion and free fall?

Projectile motion is the motion of an object that is launched into the air and moves along a curved path under the influence of gravity. Free fall, on the other hand, is the motion of an object that is only affected by the force of gravity and no other forces. In projectile motion, the object has an initial horizontal velocity, while in free fall, the object has no initial velocity in the horizontal direction.

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