- #1
galipop
- 51
- 0
f(x) = x.e^(-pi.x^2)
this is how I tried to do it...
f'(x) = x.(-pi.2.x.e^(-pi.x^2)) + 1.e^(-pi.x^2)
f'(x) = (1 - 2.pi.x^2).e^(-pi.x^2)
can anyone see anything wrong with this?
Cheers
this is how I tried to do it...
f'(x) = x.(-pi.2.x.e^(-pi.x^2)) + 1.e^(-pi.x^2)
f'(x) = (1 - 2.pi.x^2).e^(-pi.x^2)
can anyone see anything wrong with this?
Cheers