Harmonic components of a signal

In summary, the number of harmonic components in the given discrete time signal x[n] = e^{j \frac{2\pi}{3} n} is 4, with a fundamental frequency of \omega_{0} = \frac{2\pi}{3}. The harmonics are given by \omega_{k} = k\omega_{0}, for k = \pm 1, \pm 2, \pm 3, \pm 4.
  • #1
Jncik
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0

Homework Statement



I have trouble understanding what the components are

suppose we have this discrete time signal

[tex] x[n] = e^{j \frac{2\pi}{3} n} [/tex]

find the number of harmonic components

Homework Equations


The Attempt at a Solution



in my book it says that we have a set of harmonically related signals, that is signals that have a fundamental frequency that is multiple of [tex]\omega_{0}[/tex] where this omega is the fundamental frequency of x[n] in this case

so the set of this signals is [tex] x_{k}[n] = e^{j k \frac{2\pi}{3} n} [/tex]

now,

for k = 0 we have a constant

for k = +1 and -1 we have the first harmonic component since the frequency is the smae
for k = +2 and -2 we have the second harmonic component
for k = +3 and -3 the third
for k = +4 and -4 the fourth which has frequency equal to the one where k = 0

now I don't understand the questions "how many harmonic components the signal has"

assuming that for k = +4, -4 and k = 0 we have the same frequency we can count this as one

for this reason can I say that we have 4 harmonic components?

the first for k = +1 and -1, the second for k = +2 and -2, the third for k = +3 and -3 and finally the fourth for k = +4 and -4?

last question: would it be the same if I started counting from k = 0, to k = 3,-3?
 
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  • #2
Yes, you can say that there are 4 harmonic components. The fundamental frequency is given by \omega_{0} = \frac{2\pi}{3}. This means that the frequencies of the harmonics are given by \omega_{k} = k\omega_{0}, for k = \pm 1, \pm 2, \pm 3, \pm 4. So for k = +1 and -1, we have the first harmonic component. For k = +2 and -2, we have the second harmonic component, and so on. For k = +4 and -4, we have the fourth harmonic component, which has the same frequency as the fundamental frequency (since 4\omega_{0} = 4\frac{2\pi}{3} = \frac{8\pi}{3} = \frac{2\pi}{3} = \omega_{0}).It wouldn't make a difference if you started counting from k = 0, to k = 3, -3. This would still give you 4 harmonic components, since the frequency of the fourth harmonic component is the same as the fundamental frequency.
 

What are harmonic components of a signal?

Harmonic components of a signal refer to the individual sinusoidal waves that make up a periodic signal. These components have different frequencies and amplitudes, and when combined, they create the overall shape of the signal.

How are harmonic components represented in a signal?

Harmonic components are represented as sinusoidal waves in the frequency domain. This means that each component is plotted on a graph with its corresponding frequency and amplitude.

What is the importance of harmonic components in signal processing?

Harmonic components play a crucial role in signal processing as they allow us to analyze and manipulate signals in the frequency domain. This can help us identify specific frequencies and remove unwanted noise from a signal.

How do harmonic components affect the quality of a signal?

The quality of a signal is heavily influenced by its harmonic components. If the signal contains unwanted harmonics, it can result in distortion and affect the overall clarity of the signal. On the other hand, well-defined harmonic components can enhance the quality of a signal.

Can harmonic components be altered or manipulated?

Yes, harmonic components can be altered or manipulated using signal processing techniques such as filtering and modulation. This allows us to modify the frequency content of a signal and achieve specific desired effects.

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