- #1
Dustinsfl
- 2,281
- 5
Given the tidal force
$$
-\alpha\left(\frac{\hat{\mathbf{d}}}{d^2}-\frac{\hat{\mathbf{d}}_0}{d_0^2}\right)
$$
How is the potential of the tidal force
$$
-\alpha\left(\frac{1}{d}+\frac{x}{d_0^2}\right)
$$
where ##-\nabla U_{tide} = \mathbf{F}_{tide}##.
Idon't see how we get the force by taking the negative of the gradient of U.
$$
-\alpha\left(\frac{\hat{\mathbf{d}}}{d^2}-\frac{\hat{\mathbf{d}}_0}{d_0^2}\right)
$$
How is the potential of the tidal force
$$
-\alpha\left(\frac{1}{d}+\frac{x}{d_0^2}\right)
$$
where ##-\nabla U_{tide} = \mathbf{F}_{tide}##.
Idon't see how we get the force by taking the negative of the gradient of U.