- #1
whozum
- 2,221
- 1
Went to the tracks today:
Car weighs 3560 pounds, which is 1615kg.
I ran a quarter mile (402m) in 17.8s.
So naturally being the physics student I found the average acceleration to be
[tex] a = \frac{2d}{t^2} = \frac{804}{316.84} = 2.54m/s^2 [/tex]
Average force applied would then be F = m a = 1615kg * 2.54m/s^2 = 4102N
Work = 4102N * 402m = 1649044Nm
and the Power = 1649044Nm / 17.8s = 92642W = 124 horses.
What I don't get is my car is rated at 103 horses, how would I get 124 horses at the wheel? I think the error would be in the acceleration being the average acceleration, but wouldn't it come out to the same since average acceleration is pretty much "if you were accelerating at xxx m/s^2 you would have acheived the same distance in the same time". So it would pretty much be the same right?
Car weighs 3560 pounds, which is 1615kg.
I ran a quarter mile (402m) in 17.8s.
So naturally being the physics student I found the average acceleration to be
[tex] a = \frac{2d}{t^2} = \frac{804}{316.84} = 2.54m/s^2 [/tex]
Average force applied would then be F = m a = 1615kg * 2.54m/s^2 = 4102N
Work = 4102N * 402m = 1649044Nm
and the Power = 1649044Nm / 17.8s = 92642W = 124 horses.
What I don't get is my car is rated at 103 horses, how would I get 124 horses at the wheel? I think the error would be in the acceleration being the average acceleration, but wouldn't it come out to the same since average acceleration is pretty much "if you were accelerating at xxx m/s^2 you would have acheived the same distance in the same time". So it would pretty much be the same right?