- #1
Marlona Ely
- 1
- 0
Help with one of those "how much solution to equal a percentage of acid" problems!
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My problem seems to be in just how to set up the table. Once I get the figures plugged in, I can seem to work the problem. The question asks:
Minoxidil is a drug that has recently proven to be effective in treating male pattern baldness. A pharmacist wishes to mix a solution that is 2% minoxidil. She has on hand 50 ml of a 1% solution, and she wishes to add some 4% solution to it to obtain the desired 2% solution. How much 4% solution should she add?
I've set it up like: .01 50 50(.01)
.04 x x(.04)
-02 x+50 .02(x+50)
50(.01) +x(.04) = .02(x+50)
Is this the correct way to set it up?
undefinedundefinedundefined
My problem seems to be in just how to set up the table. Once I get the figures plugged in, I can seem to work the problem. The question asks:
Minoxidil is a drug that has recently proven to be effective in treating male pattern baldness. A pharmacist wishes to mix a solution that is 2% minoxidil. She has on hand 50 ml of a 1% solution, and she wishes to add some 4% solution to it to obtain the desired 2% solution. How much 4% solution should she add?
I've set it up like: .01 50 50(.01)
.04 x x(.04)
-02 x+50 .02(x+50)
50(.01) +x(.04) = .02(x+50)
Is this the correct way to set it up?