A question about energy carried by a electromagnetic wave

In summary, the energy of a classical EM wave depends on the amplitude and is given by (in Heaviside-Lorentz units) epsilon(t,x) = 1/2 * (E^2(t,x) + B^2(t,x)). On the other hand, the energy of a single photon is given by E = hv, where h is Planck's constant and v is the frequency of the wave. This means that a gamma ray has a higher energy than a radio wave, but if the frequency is the same, such as with X-rays and gamma rays, they have the same energy. The amplitude of an EM wave depends on the number of photons in the same energy state, while the energy of a single photon determines
  • #1
ckuze
9
0
My teacher told us energy at a point of a progressive wave is proportional to square of amplitude, it is true for both mechanical and electromagnetic wave.

But in the other lesson, he also tols us the energy of the EM wave is equal to hv, where h = Planck constant, v = frequency of the wave. So gamma ray has a higher energy than radiowave, but if the frequency is the same, such as X-ray and gamma ray, they have same energy.

But the EM wave still have large or small amplitude, so the energy of a EM wave depends on th frequency or amplitude or both?
 
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  • #2
The energy of a classical EM wave depends on the amplitude. The formula E = hν applies to the energy of a single photon.
 
  • #3
You have to distinguish between classical em. waves (which are quantum theoretically socalled coherent states, which are the superposition of states of any photon number corresponding to a high average photon number). For a classical electromagnetic wave in free space the energy density is given by (in Heaviside-Lorentz units)

[tex]\epsilon(t,\vec{x})=\frac{1}{2} [\vec{E}^2(t,\vec{x})+\vec{B}^2(t ,\vec{x})].[/tex]

For a single-photon state, which is not a state that can be visualized as a classical em. wave, the total energy is [itex]E=\hbar \omega=h f[/itex].
 
  • #4
Both pictures remain consistent though. If you were to take an electromagnetic wave and, while keeping the amplitude constant, change the frequency you would observe a change in the rate of photons measured per unit time. In fact, at very low frequencies and/or very low intensities you can get granularity noise due to the low rate of photons in what is called shot noise.
 
  • #5
we have just studied a little of the wave in the syllabus, so how to distinduish the classical EM wave and the single-photon state? And so for the example of gamma ray, which of the two equations can be applied? Since we have confused E = hv with E α A^2 in the example of gamma ray.
 
  • #6
You need to differentiate between a single photon and a group of photons. Photons are bosons, which means they do not obey the Pauli exclusion principle. So several photons can and do occupy the exact same quantum state. The energy E = hv is the energy of a single photon, whereas the energy that is proportional to the square of the electric field is the energy of all the photons in the same energy state. When you measure the amplitude of the electric field of a wave, you are measuring the combined effect of all the photons in that same energy state. So it also matters how many photons presently. I think the http://en.wikipedia.org/wiki/Photoelectric_effect" [Broken] demonstrates these concepts nicely.
 
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  • #7
There is a profound difference between a photon, which more precisely should be called "single-photon state". These are states with the precise photon number 1. Coherent states are superposistions of all photon-number states from 0 to [itex]\infty[/tex]. The number of photons is thus not fixed but the probability distribution for a number of photons is given by a Poisson distribution. As an intro see

http://en.wikipedia.org/wiki/Coherent_states
 
  • #8
So the energy of a EM wave is depends on the energy of a single proton, and the amplitude of the electric field is depends on how many proton in the same energy state?
 
  • #9
ckuze said:
So the energy of a EM wave is depends on the energy of a single proton, and the amplitude of the electric field is depends on how many proton in the same energy state?

It's photons that constitute light, not protons. Yes, this is basically correct. The photoelectric effect is a good example of this: You shine a beam of light on a material and electrons are knocked off. An individual electron only interacts with an individual photon, so the kinetic energy of the electrons depends on the individual photon energy and thus the frequency according to E=hv. Increasing the beam intensity applies more photons and therefore knocks out more electrons, but does not speed up each individual photon. To do that, you have to raise the frequency.
 
  • #10
Thanks all of you. Now i have understanded the difference.
 
  • #11
chrisbaird said:
... but does not speed up each individual photon. To do that, you have to raise the frequency.

This should read: "...but does not speed up each individual electron. To do that, you have to raise the frequency.
 

1. What is an electromagnetic wave?

An electromagnetic wave is a type of wave that consists of electric and magnetic fields oscillating perpendicular to each other and to the direction of wave propagation. It does not require a medium to travel through and can travel through a vacuum.

2. How is energy carried by an electromagnetic wave?

The energy of an electromagnetic wave is carried by the oscillation of the electric and magnetic fields. As the fields oscillate, they create a disturbance in space which propagates outward and carries energy with it.

3. What is the relationship between the energy and frequency of an electromagnetic wave?

The energy of an electromagnetic wave is directly proportional to its frequency. This means that as the frequency increases, so does the energy carried by the wave.

4. Can electromagnetic waves transfer energy from one place to another?

Yes, electromagnetic waves are able to transfer energy from one place to another. This is how energy from the sun reaches the Earth, as well as how energy is transmitted through radio and television signals.

5. How does the energy carried by an electromagnetic wave compare to other forms of energy?

The energy carried by an electromagnetic wave is a form of electromagnetic energy, which is a type of kinetic energy. This type of energy can also be converted into other forms, such as thermal, chemical, or electrical energy.

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