(1) Why 1900?Elaia06 said:FA*0+1900*0.8+500*1+2*FB=0
Are you sure? When I solve for FB using your original data (weight of object = 1500N) I get FB = 850 N. Which matches the answer in your book (at least according to your first post).Elaia06 said:it is 1900 sorry , I have written it the wrong way in the data.
FA*0-1900*0.8-500*1+2*FB=0
Still FB is not 860..
If the bar is uniform, the weight acts at its center. The support forces at each end will (of course) be equidistant from the center.Elaia06 said:Not related to this exercise :Ah and by the way, If we have a bar with two forces acting in the beginning and the end of it, what is the relationship of the weight of the bar with the forces? I mean, is the distance from a force to the point of weight equal to the distance of the other force with the weight or not?
A bar whose weight is evenly distributed along its length.Elaia06 said:what is a uniform bar?
Equilibrum refers to the state of a system where opposing forces or influences are balanced, resulting in a stable and unchanging state.
Understanding equilibrum is important in many fields of science, such as chemistry, physics, and biology, as it helps us predict and explain how systems will behave under different conditions.
The calculation of equilibrum depends on the specific system and variables involved. In general, it involves setting the rates of opposing reactions or forces equal to each other and solving for the equilibrium point.
Several factors can affect equilibrum, including temperature, pressure, concentration, and the presence of catalysts. Changes in these factors can shift the equilibrium point and alter the behavior of the system.
Some examples of equilibrum in the real world include the exchange of gases in our lungs and the balance of predator and prey populations in an ecosystem. Chemical reactions, such as the dissociation of water, also reach equilibrum when the rates of the forward and reverse reactions are equal.