Thermodynamics triple point

In summary: Others are not so encumbered, and may have some words of encouragement, if you post specifics.As a further hint, a good starting point is to set the two right hand sides equal to each other, and solve for T. When you run into trouble, post.In summary, the question involves finding the temperature of the triple point and the specific latent heats of vaporization and sublimation, as well as the latent heat of fusion. The equations for the sublimation and vaporization curves are given, and the problem is in the Thermodynamic Potential chapter. To start, set the two right hand sides of the equations equal to each other and solve for T. Look for "van 't Hoff" in your
  • #1
whitewanderer
2
0
This is my first post, and I am lost in this thermodynamics question. The question is as follows:

The equations of the sublimation and the vaporization curves of a particular material are given by

ln P = 0.04 -6/T (sublimation)
ln P = 0.06 - 4/T (vaporization)

where P is in atmospheres.

a) find the temperature of the triple point.
b) show the specific lateant heats of vaporization and sublimation are 4R and 6R respectively
c) Find the latent heat of fusion.

Can anyone give me somewhere to start on this problem? The problem is in the Thermodynamic Potential chapter, so I am assuming I should use the Helmholtz or the Gibbs function somehow. Any help would be awesome!

Thanks

whitewanderer
 
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  • #2
Show us what you've got so far on "a)" --- might as well start there as anywhere.
 
  • #3
I tried setting them equal, but that gave me some odd decimal point answer, and I don't think that's right. I'm basically stuck at where to go. I don't see how I can use any potential equations to get a triple point. I can see for b where the 4R and the 6R come from (obviously the term with 1/T in it) but not sure where to go from there for the second part. The third part is just like the first, where I don't know where to go with it. It's so confusing!

whitewanderer
 
  • #4
Originally posted by whitewanderer
I tried setting them equal, but that gave me some odd decimal point answer, and I don't think that's right.

Something in particular "wrong" with an "odd decimal point answer?"

I'm basically stuck at where to go. I don't see how I can use any potential equations to get a triple point.

Look for "van 't Hoff" in your text index.

I can see for b where the 4R and the 6R come from (obviously the term with 1/T in it) but not sure where to go from there for the second part. The third part is just like the first, where I don't know where to go with it.

See "Hess's Law."
It's so confusing!

whitewanderer

I will suggest that as much effort be put into reading and review of class notes as was put into evading a straight answer to what you've accomplished on "a)" --- YOU'RE the one coming here for help --- you don't cooperate with some description of what you've done, can do, and are willing to do to learn, this can turn into a very frustrating experience.

"van 't Hoff" and "Hess's law" are the legal limit for hints on this.
 
  • #5
Okay, gang, this is how NOT to use the help forums:
this thread began in General Physics and was moved to K-12?


Originally posted by whitewanderer
This is my first post, and I am lost in this thermodynamics question. The question is as follows:

The equations of the sublimation and the vaporization curves of a particular material are given by

ln P = 0.04 -6/T (sublimation)
ln P = 0.06 - 4/T (vaporization)

Anyone see anything "funny" yet? It's there. RULE ONE: double check your transcriptions of problems to the forums.
where P is in atmospheres.

a) find the temperature of the triple point.
b) show the specific lateant heats of vaporization and sublimation are 4R and 6R respectively
c) Find the latent heat of fusion.

Can anyone give me somewhere to start on this problem?

RULE TWO: read Tom's guidelines for posting to HW help.
The problem is in the Thermodynamic Potential chapter, so I am assuming I should use the Helmholtz or the Gibbs function somehow. Any help would be awesome!

Thanks

whitewanderer

Solving a system of two equations in two unknowns is trivial; when asked for specifics of what isn't intuitively satisfying, or seems "wrong" with the solution, don't disappear from the forum, state your case --- someone will be more than happy to tell you that what's wrong with the "odd decimal point answer" is that it includes a negative value for the thermodynamic temperature scale --- please check the original problem statement.

You want thermo help? Ask for it. You want thermo help AND "milk and cookies?" Dream on.

I have PM ed ww re MY lack of patience.
 

1. What is a thermodynamics triple point?

A thermodynamics triple point is a specific temperature and pressure at which a substance can exist simultaneously in all three states: solid, liquid, and gas.

2. How is the triple point determined?

The triple point is determined by measuring the temperature and pressure at which the three phases of a substance are in equilibrium.

3. Why is the triple point important?

The triple point is important because it is a unique point that defines the conditions under which a substance can exist in all three states. It is also used as a reference point for calibrating thermometers and pressure gauges.

4. Can all substances have a triple point?

No, not all substances have a triple point. The conditions required for a substance to have a triple point may not exist in our natural environment or the substance may not have all three states of matter.

5. How is the triple point used in thermodynamics?

The triple point is used in thermodynamics to study phase transitions and to determine the thermodynamic properties of a substance, such as specific heat and entropy. It is also used to create phase diagrams, which show the relationships between temperature, pressure, and phase changes for a substance.

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