- #1
XTTX
- 9
- 0
Note: I already found "an answer," and as far as I can tell it's correct; however, once you see it, you'll know why I'm suspicious of it.
Find [tex]\int\left[x\stackrel{999}{}ln\left(x\right)\right]dx[/tex]
[tex]\int\left[x\stackrel{999}{}ln\left(x\right)\right]dx[/tex]
I first started by making a tabular analysis because I believed that it would be necessary to use integration by parts. Where u = ln(x) and dv = x^999dx. Here's the expression I came up with, if you can even call it an expression. As you can see, it requires the use of sigma, which I've never had to use in this class thus far. Keep in mind that this is a high school Calculus BC class, so nothing too difficult.
[tex]\frac{x\stackrel{1000}{}}{1000}\left[ln\left(x\right)-\sum^{\infty}_{n=1}\left[\left(n-1\right)!\frac{1000!}{\left(1000+n\right)!}\right]\right][/tex]
Homework Statement
Find [tex]\int\left[x\stackrel{999}{}ln\left(x\right)\right]dx[/tex]
Homework Equations
[tex]\int\left[x\stackrel{999}{}ln\left(x\right)\right]dx[/tex]
The Attempt at a Solution
I first started by making a tabular analysis because I believed that it would be necessary to use integration by parts. Where u = ln(x) and dv = x^999dx. Here's the expression I came up with, if you can even call it an expression. As you can see, it requires the use of sigma, which I've never had to use in this class thus far. Keep in mind that this is a high school Calculus BC class, so nothing too difficult.
[tex]\frac{x\stackrel{1000}{}}{1000}\left[ln\left(x\right)-\sum^{\infty}_{n=1}\left[\left(n-1\right)!\frac{1000!}{\left(1000+n\right)!}\right]\right][/tex]