
#1
Oct1113, 01:49 PM

P: 45

Hello,
I have a question about coincidence event. Let us take the decay of deuteron to proton and alpha particle, (d, pα). p and α goes in opposite direction. So, if we put two detectors in opposite directions, one of them will detect p and another will detect α simultaneously (within a small time window). If the solid angle covered by both detectors are same (say Ω) and if one of the detector detect p then it is sure that another one will detect α. If N_{0} be the total decay rate then number of coincidence event detected will be N_{0}Ω. However, if the solid angle covered by the detectors are different, say Ω_{1} and Ω_{2} such that Ω_{1} > Ω_{2} then the number of coincidence event will be equal to the number of events detected by the second detector because other extra event detected by the larger detector won't be detected by the smaller detector. Are these reasoning right? Because in a book, I saw the number of coincidence event is N_{0}Ω_{1}Ω_{2}. Thanks. 



#2
Oct1113, 07:25 PM

Mentor
P: 10,840

A deuteron is a stable nucleus with a single proton and a neutron. It cannot decay in the way you describe.
Lithium5 quickly decays to proton+alpha particle  you have to produce it directly before the decay, and this usually will not happen without any momentum transfer. If your decay is back to back: 


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