- #1
compwiz3000
- 17
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When I do some physics derivation, I find that on a seesaw, if the object is farther away from the fulcrum, the angular acceleration decreases. Is this true? If not, where did I go wrong?
[tex]\tau = I \cdot \alpha[/tex]
[tex]\tau=F \cdot r[/tex]
Then, [tex]\alpha = \frac{F \cdot r}{I} = \frac{F_g \cdot r}{mr^2}=\frac{g \cdot m \cdot r}{mr^2}=\frac{g}{r}[/tex], so if the distance "r" increases, angular acceleration decreases...did I do something wrong?
[tex]\tau = I \cdot \alpha[/tex]
[tex]\tau=F \cdot r[/tex]
Then, [tex]\alpha = \frac{F \cdot r}{I} = \frac{F_g \cdot r}{mr^2}=\frac{g \cdot m \cdot r}{mr^2}=\frac{g}{r}[/tex], so if the distance "r" increases, angular acceleration decreases...did I do something wrong?
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