Simple calorimetry problem, melting of water

[qpham26]

Homework Statement

Calculate the final temperature (once the ice has melted) of a mixture made up initially of 75.0 mL liquid water at 29 degrees celsius and 7.0 g ice at 0.0 degrees celsius.

Homework Equations

c: heat capacity of water
m_iceΔH_f + m_icec(T_f-0°C) = -m_waterc(T_f - 29°C)

The Attempt at a Solution

So basically I will do some algebra to solve for T_f

Can someone help me confirm the set up above?

Thanks very much.

 

[nate808]

Hello there,

Your setup looks good! Just to confirm, here is the complete equation:

(75.0 mL) x (c) x (Tf - 29°C) = -(7.0 g) x (miceΔHf) - (7.0 g) x (c) x (Tf - 0°C)

Where c is the heat capacity of water, miceΔHf is the enthalpy of fusion of ice, and Tf is the final temperature.

To solve for Tf, you can use the following steps:

1. Distribute the - sign on the right side of the equation.
2. Combine like terms.
3. Move all terms with Tf to one side of the equation.
4. Factor out Tf.
5. Divide both sides by the coefficient of Tf.
6. Solve for Tf.

I hope this helps! Let me know if you have any other questions. Good luck with your calculations!