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Equilibrium Distribution of Electrons and Holes |
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| Feb9-13, 01:53 PM | #1 |
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Equilibrium Distribution of Electrons and Holes
Hello. I was studying the Semiconductor and I am confused with this diagram.
I have attached the diagram. Please tell me briefly what does this diagram say. So that I could ask further. I have confusion with this diagram. I don't want to be specific so that you describe the whole diagram briefly and I will try to understand it. Thank you. |
| Feb9-13, 02:18 PM | #2 |
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fF(E) is the probability that a state is occupied, as determined by the Fermi distribution (left=0, right=1). It is close to 0 for states of high energy (top part of the plot) and close to 1 for states of low energy (bottom).
gc is the density of states in the conducting band with that specific energy - it is zero at Ec and increasing for higher energy. To find the number of electrons with a specific energy, you multiply both functions, and get the shaded area. Its area is (proportional to) the total number of electrons. gv is the same in the valence band. |
| Feb10-13, 01:57 AM | #3 |
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@mfb
Thank you for your kind reply. Here is another image. I am confused with a sentence "We note previously that the function f(E) for E>EF is symmetrical to .........", last four line of the first paragraph. Would you please help me in understanding how f(E) for E=Ef+dE is equal to the function 1-f(E) for E=Ef-dE. Thank you. |
| Feb10-13, 07:27 AM | #4 |
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Equilibrium Distribution of Electrons and Holes
I don't see another image.
Close to the Fermi energy and for small temperatures (always true in semiconductors), the function is nearly point symmetric with f(EF)=1/2 as symmetry point. That relation is just another way to express this symmetry. |
| Feb10-13, 10:16 AM | #5 |
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Here is another image. sorry friend.
Now you can see the last 4 lines of the first paragraph in the given image. Thank you for your reply. |
| Feb12-13, 04:52 AM | #6 |
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Anyone help me
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| Feb12-13, 09:41 AM | #7 |
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I don't see any open questions.
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| Feb12-13, 01:30 PM | #8 |
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Hello friend.
What do you mean by open question? I am asking you to clear the last four line of the first paragraph from the attached image. Thank you. |
| Feb12-13, 03:02 PM | #9 |
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I posted an explanation in post 4.
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| Feb13-13, 07:19 AM | #10 |
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I read your post several times and I got what you have said. Thank you. It is cleared now. I hope you will help me next time if I post another thread for help.
Thank you. |
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