- #1
DizzyDoo
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[SOLVED] Checking: Circle Equations Questions
Last time I got people to check my homework here, I got things marked wrong when they where said to be right. Let's see if it happens again...
(1) The circle C has centre (3, 4) and passes through the point (8, 8).
Find an equation for C.
(2) Find the centre and radius of the circle x² + y² + 4x + 6y – 17 = 0
(3) A(4, 0) and B(3, 5) are the end points of a diameter of the circle C.
Find (a) the exact length of AB,
(b) the coordinates of the midpoint P of AB,
(c) an equation for the circle C.
None
Right here is my working for (1)
Since we know the circle centre and a point the circle passes through, I can use pythag to work on the radius right? It seems a little too simple to work, but I can't see anything wrong with it. After drawing a clear diagram;
(4+8)² + 5² = r²
r² = 144 + 25
r² = 169
r = 13
Therefore the equation must be (x-3)² + (y-4)² = 13
Correct?
Now, my working for (2);
The equation needs to be factorised, so I have to "complete the square" to get the stuff inside the brackets. This is usually where I go wrong, so check this bit carefully please!
(x+2)² - 4 + (y+3)² - 9 - 17 = 0
Rearraged:
(x+2)² + (y+3)² = 17
Ah, I have to go now, but I'll post the answers to 3 quickly:
a) I got 5.09
b) x = 3.5
y = 2.2
and
c) (x+3.5)² + (y+2.2)² = 5.09
Sorry about that lack of working out. Thank you for your time if you've read this far!
Last time I got people to check my homework here, I got things marked wrong when they where said to be right. Let's see if it happens again...
Homework Statement
(1) The circle C has centre (3, 4) and passes through the point (8, 8).
Find an equation for C.
(2) Find the centre and radius of the circle x² + y² + 4x + 6y – 17 = 0
(3) A(4, 0) and B(3, 5) are the end points of a diameter of the circle C.
Find (a) the exact length of AB,
(b) the coordinates of the midpoint P of AB,
(c) an equation for the circle C.
Homework Equations
None
The Attempt at a Solution
Right here is my working for (1)
Since we know the circle centre and a point the circle passes through, I can use pythag to work on the radius right? It seems a little too simple to work, but I can't see anything wrong with it. After drawing a clear diagram;
(4+8)² + 5² = r²
r² = 144 + 25
r² = 169
r = 13
Therefore the equation must be (x-3)² + (y-4)² = 13
Correct?
Now, my working for (2);
The equation needs to be factorised, so I have to "complete the square" to get the stuff inside the brackets. This is usually where I go wrong, so check this bit carefully please!
(x+2)² - 4 + (y+3)² - 9 - 17 = 0
Rearraged:
(x+2)² + (y+3)² = 17
Ah, I have to go now, but I'll post the answers to 3 quickly:
a) I got 5.09
b) x = 3.5
y = 2.2
and
c) (x+3.5)² + (y+2.2)² = 5.09
Sorry about that lack of working out. Thank you for your time if you've read this far!