Integrating tan x ln x cos x: A Guide to Solving Indefinite Integrals

In summary, the indefinite integral is equivalent to \int sin~x\cdot ln~x\ dx and can be solved using integration by parts. The resulting antiderivative is -\cos \left( x \right) \ln \left( x \right) +{\it Ci} \left( x\right) , where Ci(x) is the Cosine Integral. However, to get the answer for the original integral, it is necessary to differentiate the antiderivative obtained.
  • #1
James889
192
1
Hi,

Looking to integrate the indefinite integral:

[tex]\int tan~x\cdot ln~x\cdot cos~x[/tex]

Since tan x = sin x/ cos x, this integral be written as [tex]\int sin~x\cdot ln~x[/tex]

In that case i thought the answer was cot x. But that is wrong.

Do you need to use integration by parts on this one?
 
Last edited:
Physics news on Phys.org
  • #2
I just tried to evaluate this integral in Mathematica, but this does not return an analytical solution... so I doubt there is one. But maybe someone else has an idea?
 
  • #3
James889 said:
Hi,

Looking to integrate the indefinite integral:

[tex]\int tan~x\cdot ln~x\cdot cos~x[/tex]

Since tan x = sin x/ cos x, this integral be written as [tex]\int sin~x\cdotln~x[/tex]

In that case i thought the answer was cot x. But that is wrong.

Do you need to use integration by parts on this one?

The integral sounds so unco and tricky at the first glance. But later you'll find out that it is equivalent to [tex]\int sin~x\cdot ln~x\ dx[/tex] after cancelling the cos(x) with that of tangant function. So letting f'(x) = sin(x) and g(x) = ln(x) and using integration by parts gives us [tex]-\cos \left( x \right) \ln \left( x \right) +{\it Ci} \left( x\right) [/tex]. Note that here we assume that x is greater than zero. otherwise the above antiderivative will get some complex term. At x=0, it is not defined.

Here Ci(x) is some kind of special funcion called Cosine Integral which is exactly the second part in the integration you are supposed to do.

AB
 

1. What is an indefinite integral?

An indefinite integral is a mathematical concept used in calculus to find the antiderivative of a function. It is the opposite of a derivative, and it is represented by the symbol ∫ (the integral sign).

2. How is an indefinite integral different from a definite integral?

An indefinite integral does not have specific limits of integration, whereas a definite integral has both an upper and lower limit. This means that an indefinite integral represents a family of functions, while a definite integral gives a single numerical value.

3. How do you solve an indefinite integral?

To solve an indefinite integral, you must use integration techniques such as integration by parts or substitution. These techniques allow you to find the antiderivative of a function, which is the original function without the constant of integration.

4. What is the purpose of an indefinite integral?

The purpose of an indefinite integral is to find a function that, when differentiated, will give the original function. It is particularly useful in physics and engineering, where it is used to find quantities such as displacement, velocity, and acceleration from known equations.

5. Can you evaluate an indefinite integral at a specific point?

No, you cannot evaluate an indefinite integral at a specific point because it represents a family of functions. However, you can find the value of a definite integral at a specific point by plugging in the limits of integration and solving for the numerical value.

Similar threads

  • Calculus and Beyond Homework Help
Replies
3
Views
332
  • Calculus and Beyond Homework Help
Replies
19
Views
1K
  • Calculus and Beyond Homework Help
Replies
15
Views
775
  • Calculus and Beyond Homework Help
Replies
7
Views
690
  • Calculus and Beyond Homework Help
Replies
6
Views
542
  • Calculus and Beyond Homework Help
Replies
22
Views
1K
  • Calculus and Beyond Homework Help
Replies
2
Views
863
  • Calculus and Beyond Homework Help
Replies
27
Views
3K
  • Calculus and Beyond Homework Help
Replies
2
Views
792
  • Calculus and Beyond Homework Help
Replies
22
Views
1K
Back
Top