Abu Abdallah said:In The L=0 states in Hydrogen atom, the electron has a maximum probablity to exist at r=0 ( at the location of the proton ) Is this logical? What prevents the electron then from falling on the proton? There is no angular momentum to prevent that !
Patrick is right: the probability density peaks at the Bohr radius.Abu Abdallah said:In The L=0 states in Hydrogen atom, the electron has a maximum probablity to exist at r=0 ( at the location of the proton ) Is this logical? What prevents the electron then from falling on the proton? There is no angular momentum to prevent that !
nrqed said:The probability density is [itex] \vert \psi(\vec r,t) \vert^2 dV [/itex], not [itex] \vert \psi(\vec r,t) \vert^2 [/itex]. Because of the r^2 in the volume element dV you actually find that the probaility density is suppressed near the origin!
Patrick
Abu Abdallah said:nrqed, calculate the probabiliyt density with respect to another frame (whose origin not at the proton) and you will find that [itex] \vert \psi(\vec r,t) \vert^2 [/itex] has a maximum at the proton while the volume element is not zero there.
Abu Abdallah said:nrqed, calculate the probabiliyt density with respect to another frame (whose origin not at the proton) and you will find that [itex] \vert \psi(\vec r,t) \vert^2 [/itex] has a maximum at the proton while the volume element is not zero there.
None of the four forces. You know the first force from classical physics. You don’t know the second because it's purely quantum. Besides, it's not a force but a tendency that every relative position has: to grow fuzzier unless counterbalanced by an attractive force that gives rise to the opposite tendency. Nothing needs to act on a fuzzy relative position to make it grow fuzzier. This tendency, encapsulated by the uncertainty principle (to stick to the conventional name) is part and parcel of the quantum behavior of matter.Abu Abdallah said:Koantum, I know the force that attracts the electron to the proton : it's Coulomb's force. But what is this force that tries to impose the Fuzziness principle ? which one of the four force is it?
In the L=0 state, the electron and proton are in a state of equilibrium where they are attracted to each other by the electromagnetic force. However, the electron also experiences repulsion from the proton due to its own negative charge. This balance between attraction and repulsion prevents the electron from sticking onto the proton.
The lack of electron sticking to the proton in the L=0 state is a result of the quantum mechanical properties of the electron and the proton. The electron behaves as a wave and can only exist in certain discrete energy levels, while the proton has a fixed positive charge. These properties do not allow for the electron to stick onto the proton in the L=0 state.
Yes, in higher energy states the electron can stick to the proton due to the increased attraction between the two particles. In these states, the electron's wave function overlaps with the proton's nucleus, allowing for a stable binding between the two particles.
In the L=0 state, the electron is in the lowest energy level and is not able to stick to the proton due to the balance of forces mentioned earlier. In higher energy states, the electron is able to stick to the proton as it has more energy and can overcome the repulsion from the proton's positive charge.
No, the electron cannot stick to the proton in the L=0 state as it would require a change in the quantum mechanical properties of the electron and the proton. This is not possible as these properties are fundamental to the nature of these particles and cannot be changed without external forces acting on them.