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Nonrelativistic deflection 
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#19
Aug414, 02:05 AM

PF Gold
P: 636

I am trying to understand the rationale of the formula, in the first place: the ray is moving tangentially at 3*10^{10} cm/s it gets a normal velocity 127 700 cm/s , right? when we divide v/c = 127 700/3*10^{10} = tanθ = 0.000004256 we are dividing the legs of a rectangle and we get tan θ, which should be the angle of deflection, right? Why do you need to approximate the tangent to the angle or to its sine, why don't you simply do tan^{1} θ ? 


#20
Aug414, 11:38 AM

P: 482




#21
Aug414, 11:25 PM

PF Gold
P: 636

The point is anyway the angle, if we know its tangent v/c = tanθ, why aproximate it to the angle and not simply derive tan^{1}? And, again, as we are considering non relativistic deflection, what happens when we apply to the earth, deflected by the sun? Thanks for your help 


#22
Aug514, 12:17 PM

P: 482




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