Spherical geometry, some simple things

In summary, this person is trying to work their way through a text on geometry, and has struggled with the first section. They are stuck on a problem involving the arc length of an arc on a circle, and are looking for advice from someone more experienced.
  • #1
trancefishy
75
0
So, I'm working my way through "Geometry from a Differentiable viewpoint" (or, trying to get through section 1.1, anyways).

right now, it's spherical geometry. so far, a great circle has been defined as the set of points on the sphere that intersect with a plane that intersects the origin of the sphere. The area of a lune, the "sherical pythagorean theorem", and the spherical sine theorem have all been presented with very brief proofs. It has taken me 5 hours of good work to get through 5 pages of this stuff.

the exercise that I'm doing is this : "The sphere of radius one can be coordinatized as teh set of points [tex](x,y,z)[/tex] in [tex]\mathbb{R}^3[/tex] satisfying [tex]x^2 + y^2 + z^2 = 1 [/tex], or as the set of points [tex](1,\psi,\theta)[/tex] in spherical coordinates, with [tex]0 \leq \psi \leq 2\pi [/tex], and [tex]0 \leq \theta \leq \pi [/tex]. In these two coordinate systems, determine the distance along great circles between two arbitrary points on the sphere as a function of the coordinates."

I worked on this thing for quite a while, first in spherical coordinates (they make more sense), then, deciding maybe i should use the [tex]\mathbb{R}^3[/tex] coordinate grid. i got essentially nowhere. finally, i looked at the answer, hoping to see something I missed. I did, kind of, but after working on those, i still don't have any idea how they got the answers, and I feel like I'm missing something essential to doing this stuff.

the Answers are : for [tex]\mathbb{R}^3[/tex], the great-circle distance between A and B (the arbitrary points) = [tex]\arccos(A \cdot B)[/tex], and for spherical coordinates is [tex]\arccos (\cos (\psi_1 - \psi_2)\sin \theta_1 \sin \theta_2 + \cos \theta_1 \cos \theta_2)[/tex]

So, if anyone can tell me maybe what I could read to get myself filled in on this, that would be great. I haven't looked at this in a couple days, so, I'm going to go ahead and continue working on it, and checking up on this, as this book looks super cool, but I want to make sure I have the proper foundations. By the way, i have taken and aced calc I and II, and matrix theory/linear algebra, so that you know what kind of background I have.
 
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  • #2
The length (s) of an arc on a circle is simply the product of the radius and the inscribed angle [itex]\theta[/itex], so

s = r [itex]\theta[/itex].

And the circumference is just 2[itex]\pi[/itex]r.

On a sphere, the arc length between two points is given by the same relation, and represents the loci of points defined by the intersection of the plane defined by the two vectors and the spherical surface and bound by the two points of interest.

Thus if one has two vectors of radius, r, the length of an arc on the surface of the sphere is given by the product of r and the angle between the vectors, and that angle can be found from

[itex]\vec{A_1}\,\cdotp\,\vec{A_2} = A_1 A_2 cos\, \theta[/itex]

and for r = 1, then [itex] A_1 = A_2 = 1[/itex],

and the angle [itex]\theta[/itex] is simply the arccos of the dot product.

Try to write two vectors in spherical condinates [itex](1, \psi_1, \theta_1 )[/itex] and [itex](1, \psi_2 ,\theta_2)[/itex] and take the dot product on the unit sphere.
 
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  • #3
Let [itex] \vec{A} [/itex] and [itex] \vec{B} [/itex] two arbitrary vectors who share the same origin and that is chosen as the origin of the Oxyz coordinate system.
Consider the scalar product between the 2 vectors:
[tex] \vec{A}\cdot\vec{B} =|\vec{A}||\vec{B}| \cos \theta [/tex] (*)
,where [itex] \theta [/itex] is the angle between the 2 vectors (remember they share the same origin).
Now use the fact that the vectors are somehow related to the orthonormal system of coordinates.
Then u can write:
[tex] \vec{A}=|\vec{A}|\sin \theta_{1}\cos \phi_{1}\vec{i}+|\vec{A}|\sin \theta_{1}\sin \phi_{1}\vec{j}+|\vec{A}|\cos \theta_{1}\vec{k} [/tex]
[tex] \vec{B}=|\vec{B}|\sin \theta_{2}\cos \phi_{2}\vec{i}+|\vec{B}|\sin \theta_{2}\sin \phi_{2}\vec{j}+|\vec{B}|\cos \theta_{2}\vec{k} [/tex]

Make the scalar product and then obtain:
[tex]\vec{A}\cdot{\vec{B}=|\vec{A}||\vec{B}| [\cos \theta_{1}\cos \theta_{2}+\sin \theta_{1}\sin \theta_{2}\cos(\phi_{1}-\phi_{2})] [/tex] (**)

Equate the formulas denoted by (*) and (**),simplify through the product of the moduli of the 2 vectors and finally obtain:

[tex] \cos \theta=\cos \theta_{1}\cos \theta_{2}+\sin \theta_{1}\sin \theta_{2}\cos(\phi_{1}-\phi_{2}) [/tex](***)
,which is exactly the formula u were looking for.
As u can see,my method is structurally similar with the one by Astronuc,but my vectors are not necessarily unit vectors.They're not even of equal modulus.

Problem:Take an atlas and compute the geodesical distance in Km between NewYork and San Francisco.
HINTS:Consider Earth as a sphere.Find the mean radius (probably given in the atlas),use the formula (***).Carefully,though.

Daniel.

PS.Math is beauty... :wink:
 
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  • #4
Thanks you very much :-) though i don't get the satisfaction of having done it myself now, but, at least i get it...
 

1. What is spherical geometry?

Spherical geometry is a branch of mathematics that studies the properties and measurements of shapes and figures on a spherical surface, such as the Earth. Unlike Euclidean geometry, which deals with flat surfaces, spherical geometry takes into account the curvature of a sphere.

2. What are some examples of spherical shapes?

Some examples of spherical shapes include the Earth, the Moon, the Sun, and other planets. Spheres are also commonly used to represent objects such as atoms and cells in scientific illustrations.

3. How is distance measured in spherical geometry?

In spherical geometry, distance is measured along the surface of a sphere instead of in a straight line. This is known as the great-circle distance, which is the shortest distance between two points on a sphere. It is commonly used in navigation and cartography.

4. What are the basic postulates or axioms of spherical geometry?

The basic postulates or axioms of spherical geometry include the idea that a line is the shortest path between two points, that all right angles are congruent, and that there is no limit to the size of a circle. These postulates differ from those in Euclidean geometry due to the curvature of a sphere.

5. How is spherical geometry used in real life?

Spherical geometry has many practical applications in real life, including navigation, astronomy, and cartography. It is also used in fields such as geography, geology, and physics to study the Earth and other spherical objects. Additionally, spherical geometry plays a crucial role in the development of global positioning systems (GPS) and satellite imagery.

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