Solving the Equatorial Problem: A Journey of a Rope Around the Earth

  • Thread starter Milind_shyani
  • Start date
In summary, the length of a rope around the Earth's equator increases by 100 cm when it is extended by 100 cm. This results in a small difference in the radii of the Earth and the circle formed by the lifted rope, which can be calculated using mathematical formulas. This phenomenon may seem counterintuitive, but it can be understood by considering how a square fits tightly around a circle.
  • #1
Milind_shyani
42
0
Hi pls read this its worth it.(assujme Earth as a complete sphere)
suppose i stand in india(place where equator passes) right now and now i begin my journey with a rope thousnands of kilometers long i follow the journey exactly on equator and return to the same place in india.means ihave tied a knot on the whole Earth with the rope. the length of the rope would be equal to the lenth of the equator. Now suppose that i increase the lenth of the rope by 100 cm.so now as the rope's lenth haas increased it will get loosened by a small bit.
Now suppose that thousnds of men are standing side by sid along the equator.
now as the rope's lenthg has increased(by 100 cm) the rope would become loose.so these men along the equator will be able to lift the rope.ie the rope has become loose so each men standing side by side along the equator will liftthe rope.now as the rope is lifted by each men equally.the rope would itself form a huge circle whose circumference would be greater then Earth by 100 cm.
now as the circum is greater,the radius(of the circle of rope) would be greater than the radius of the Earth by a very very very small amount. the difference bbetween the radius of the Earth and the radius of the circle of the rope would infact be the measure of the lift by the men of the rope. now this lift would be some 1or2 nanometer as common sense says.lets see the math way
radius of earth=r
radius of the circle of rope=R
now
2piR=2pir+100cm
2piR-2pir=100cm
2pi(R-r)=100cm
R-r=100/2pi
R-r=100/2*3.14
R-r=15.92 cm
Means appr 16 cm.SO BY JUST ADDING 100CM TO THE ROPE THERE IS A DIFF OF 16 CM IN THE RADII. i tried it on a cricket ball,a basket ball and thee answer comes same 16.00 cm
I hope you get the problem if not tell me i will try to explain it in a better way.
courtesy-million to 1
 
Mathematics news on Phys.org
  • #2
Ahh, brings back some memories! This was actually part of the first question at my interview when I applied for my undergad degree at unniveristy.
 
  • #3
Milind_shyani said:
Hi pls read this its worth it.(assujme Earth as a complete sphere)
suppose i stand in india(place where equator passes) right now and now i begin my journey with a rope thousnands of kilometers long i follow the journey exactly on equator and return to the same place in india.means ihave tied a knot on the whole Earth with the rope. the length of the rope would be equal to the lenth of the equator. Now suppose that i increase the lenth of the rope by 100 cm.so now as the rope's lenth haas increased it will get loosened by a small bit.
Now suppose that thousnds of men are standing side by sid along the equator.
now as the rope's lenthg has increased(by 100 cm) the rope would become loose.so these men along the equator will be able to lift the rope.ie the rope has become loose so each men standing side by side along the equator will liftthe rope.now as the rope is lifted by each men equally.the rope would itself form a huge circle whose circumference would be greater then Earth by 100 cm.
now as the circum is greater,the radius(of the circle of rope) would be greater than the radius of the Earth by a very very very small amount. the difference bbetween the radius of the Earth and the radius of the circle of the rope would infact be the measure of the lift by the men of the rope. now this lift would be some 1or2 nanometer as common sense says.lets see the math way
radius of earth=r
radius of the circle of rope=R
now
2piR=2pir+100cm
2piR-2pir=100cm
2pi(R-r)=100cm
R-r=100/2pi
R-r=100/2*3.14
R-r=15.92 cm
Means appr 16 cm.SO BY JUST ADDING 100CM TO THE ROPE THERE IS A DIFF OF 16 CM IN THE RADII. i tried it on a cricket ball,a basket ball and thee answer comes same 16.00 cm
I hope you get the problem if not tell me i will try to explain it in a better way.
courtesy-million to 1

Now i would like to know that how it happens it is against common sense.
 
  • #4
Why is it against common sense?
 
  • #5
Milind_shyani said:
Now i would like to know that how it happens it is against common sense.
Why is it against common sense? You've just shown why it happens.

Edit: Damn Curious, you're on the ball today...
 
Last edited:
  • #6
Hint, what is 1/2pi, approx.
 
  • #7
If you want a common sense reason, consider how a square acts:

Make a big square that fits tightly around a circle (maybe a basketball, maybe the earth). Now increase the circle's radius by 5: how much more square do you need?

Well, you need to add 10cm to each side, while would spread the top and bottom by 10cm and the left and right by 10cm, making it fit tightly around the circle again.

The circle case is very similar to this. Consider that a circle of radius r always has a perimeter less than the perimeter of a square of width 2r: if the circle's perimeter increased any faster than the square's, it would eventually need to have the square inside it!
 
Last edited:

1. How does the journey of a rope around the Earth solve the equatorial problem?

The equatorial problem refers to the mathematical challenge of finding the shortest distance between two points on the surface of a sphere. By looping a rope around the Earth's equator, we create a perfect circle with a circumference of approximately 40,075 kilometers. This distance is the shortest possible path around the Earth, making it the solution to the equatorial problem.

2. What is the significance of the equatorial problem?

The equatorial problem has been a significant challenge in mathematics for centuries. It has practical applications in fields such as navigation, engineering, and geography. The solution also has implications for understanding the Earth's shape and size.

3. How accurate is the solution of using a rope around the Earth's equator?

The solution of using a rope around the Earth's equator is considered to be highly accurate. The circumference of the Earth at the equator is 40,075 kilometers, while the actual distance varies slightly due to the Earth's ellipsoidal shape. However, for most practical purposes, the rope's length is considered to be an accurate representation of the Earth's circumference.

4. Can this method be used to solve similar problems on other spherical objects?

Yes, this method can be used to solve similar problems on other spherical objects. As long as the object has a defined circumference, we can use a rope or string to find the shortest distance around it. This method is commonly used in cartography to measure and represent the circumference of other celestial bodies, such as planets and moons.

5. Is there a limit to the size of the object that can be solved using this method?

Technically, there is no limit to the size of the object that can be solved using this method. However, for objects with extremely large circumferences, such as the sun or other stars, the accuracy of the solution may be affected by the object's irregular shape. Additionally, the practicality of physically looping a rope around such large objects may also be a limiting factor.

Similar threads

Replies
18
Views
3K
  • Introductory Physics Homework Help
Replies
4
Views
4K
  • Introductory Physics Homework Help
Replies
12
Views
2K
  • Introductory Physics Homework Help
Replies
18
Views
2K
Replies
1
Views
572
  • Introductory Physics Homework Help
Replies
19
Views
785
  • Introductory Physics Homework Help
Replies
2
Views
870
  • Introductory Physics Homework Help
Replies
24
Views
4K
  • Engineering and Comp Sci Homework Help
Replies
4
Views
2K
  • Introductory Physics Homework Help
Replies
8
Views
2K
Back
Top