- #1
MikalP
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Homework Statement
A 200-kg crate is pushes horizontally with a force of 700 N. If the coefficient of friction is 0.20, calculate the acceleration of the crate.
Homework Equations
Well, at the moment I'm just wondering if I used the right equations, and if not then a heads up on where I went wrong
Would I start with Ffr = u x Fn
and then proceed to a = Fnet / m?
The Attempt at a Solution
Fn = 200kg x 9.8 = 1960
Ffr = u x Fn, so 1960 x .20 = 392.
Ffr = 392.
a = Fnet / m,
Fnet = Fapplied + Ffr = 700N + 392 = 1092
[Removed Fg and Fn since they cross out as the block is not falling or rising]
Fnet / m = 1092 / 200 = 5.46 m/s
= = = =
I have another question that I'm currently stuck on but have yet to totally give it a try, so I will post the question and update it accordingly.
Homework Statement
Safety engineers estimate that an elevator can hold 20 persons of 75-kg average mass. The eleveator itself has a mass of 500 kg. Tensile strength tests show that the cable supporting the elevator can tolerate a maximum force of 2.96 x 10^4 N. What is the greatest acceleration the elevator's motor can produce without breaking the cable.