Gravtational Potential Energy

In summary, the conversation discusses the amount of energy needed to place a satellite into circular Earth orbit and how much additional energy would be required to escape the Earth's gravitational field. The equation used to calculate the work of placement is provided and it is mentioned that the initial speed of the satellite due to Earth's rotation may also play a role. The second question involves finding the binding energy.
  • #1
Lolagoeslala
217
0

Homework Statement



9. What is the total energy needed to place a 2.0 x 10^3-kg satellite into circular Earth
orbit at an altitude of 5.0 x10^2 km?

10. How much additional energy would have to be supplied to the satellite in question 9
once it was in orbit, to allow it to escape from Earth’s gravitational field?

The Attempt at a Solution



9. I was trying to use the equation

Wpl = (- GMem/Ro) - (-GMem/Re)
Wpl = ( - (6.67 x10^-11 Nm^2/s^2)(5.98 x10^24)(2 x 10^3 kg)/(5 x10^5m)+(6.38 x10^6m)) - (- (6.67 x10^-11 Nm^2/s^2)(5.98 x10^24)(2 x 10^3 kg)/6.38 x10^6m))

Wpl = - 11.59494186 x 10^10 + 12.50363636 x10^10
Wpl = 0.908717 x 10^10 J

IS THIS CORRECT?

and what can i do for Question 10 ?
 
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  • #2
Placing a satellite in orbit requires not only that you move it up to the required distance in the Earth's gravitational field, but also that you impart the required speed for it to orbit (otherwise it would just fall straight back down). So there's gravitational PE involved as well as KE.

One point that's not covered in the problem statement is whether or not you can take advantage of the initial speed of satellite due to it being launched from the surface of a rotating Earth; If you launch from the equator in the appropriate direction, you begin with an initial speed due to the Earth's daily rotation.
 
  • #3
gneill said:
Placing a satellite in orbit requires not only that you move it up to the required distance in the Earth's gravitational field, but also that you impart the required speed for it to orbit (otherwise it would just fall straight back down). So there's gravitational PE involved as well as KE.

One point that's not covered in the problem statement is whether or not you can take advantage of the initial speed of satellite due to it being launched from the surface of a rotating Earth; If you launch from the equator in the appropriate direction, you begin with an initial speed due to the Earth's daily rotation.

ok so ... i am guessing you use the work of placement to find the speed?
 
  • #4
Lolagoeslala said:
ok so ... i am guessing you use the work of placement to find the speed?
No, the work of placement is what you're trying to determine. How fast does a satellite in circular orbit at radius r have to be traveling to stay there?
 
  • #5
haruspex said:
No, the work of placement is what you're trying to determine. How fast does a satellite in circular orbit at radius r have to be traveling to stay there?

yes that's for number 9 .. you are completely right about that;... but for the number 10 .. second question you are finding the binding energy correct?
 

What is gravitational potential energy?

Gravitational potential energy is the energy an object possesses due to its position in a gravitational field. It is the potential for an object to do work as a result of its position above the ground.

How is gravitational potential energy calculated?

Gravitational potential energy is calculated by multiplying an object's mass by the acceleration due to gravity (9.8 m/s^2) and its height above the ground. The formula is: GPE = mgh, where m is mass, g is acceleration due to gravity, and h is height.

What is the relationship between gravitational potential energy and height?

The relationship between gravitational potential energy and height is directly proportional. This means that as an object's height increases, its gravitational potential energy also increases.

Is gravitational potential energy the same as potential energy?

No, gravitational potential energy is a type of potential energy that is specific to an object's position in a gravitational field. Potential energy, on the other hand, refers to the energy an object possesses due to its position or configuration in any type of force field.

What are some real-life examples of gravitational potential energy?

Some examples of gravitational potential energy include a roller coaster at the top of a hill, a book on a shelf, and a pendulum at its highest point. In each of these examples, the object has the potential to do work as a result of its position in a gravitational field.

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