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Wave Function Collapse and Entropy |
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| Feb1-13, 07:25 AM | #18 |
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Wave Function Collapse and Entropy |
| Feb1-13, 07:41 AM | #19 |
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| Feb1-13, 08:19 AM | #20 |
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I'm still wondering how exactly this is related to the observable entropy increases. If we start with two pure states, I guess that any fundamental interaction that leads to maximal entanglement should begin to disentangle the systems afterwards. So I would expect an oscillating entropy for the systems (in classical mechanics, no entropy change arises from such a situation). Which of course would call for an explanation why our observations always take place in the rising entropy domain. |
| Feb1-13, 08:25 AM | #21 |
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| Feb1-13, 08:45 AM | #22 |
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A Born-rule-independent motivation for doing the partial trace is the fact that the evolution of the resulting object (reduced density matrix) does not depend on the whole Hamiltonian, but only on the Hamiltonian for the subsystem. |
| Feb1-13, 09:00 AM | #23 |
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The good question is why the direction in which entropy increases is everywhere the same, i.e., why it is not the case that entropy increases in one subsystem and decreases in another? The answer is that it is interaction between the subsystems which causes them to have the same direction of the entropy increase: http://arxiv.org/abs/1011.4173v5 |
| Feb1-13, 09:16 AM | #24 |
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| Feb1-13, 09:27 AM | #25 |
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A much more refined analysis of that stuff, but still very non-technical, is the book: H. Price, Time's Arrow and Archimedes Point Another good related non-technical book is: D. Z. Albert, Time and Chance There is also a good non-technical chapter on that in: R. Penrose, The Emperor's New Mind |
| Feb2-13, 12:30 AM | #26 |
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| Feb2-13, 07:34 AM | #27 |
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| Feb2-13, 07:53 AM | #28 |
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| Feb2-13, 08:08 AM | #29 |
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The collapse interpretation says that initially the system is in some state [itex]\vert \Psi\rangle[/itex]. You perform an experiment to measure some observable with eigenvalues [itex]\lambda[/itex] and corresponding eigenstates [itex]\vert \Psi_\lambda\rangle[/itex] (for simplicity, assume non-degeneracy). Then the results are that afterward: For every value of [itex]\lambda[/itex], there is a probability of [itex]\vert \langle \Psi \vert \Psi_\lambda\rangle \vert^2[/itex] that the system is in state [itex]\vert \Psi_\lambda\rangle[/itex] This is captured by the density matrix formalism as the transition [itex]\vert \Psi \rangle \langle \Psi \vert \Rightarrow \sum_\lambda \vert \langle \Psi \vert \Psi_\lambda\rangle \vert^2 \vert \Psi_\lambda \rangle \langle \Psi_\lambda \vert[/itex] |
| Feb2-13, 01:56 PM | #30 |
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I guess thinking about it classically, Demystifier's argument must be right. Measurement gives us more information, which is a reduction in entropy. Entropy increases when we forget, according to Landauer's exorcism of Maxwell's demon.
I guess what's not obvious to me is - how much coarse graining do we need, since the partial trace in getting the reduced density matrix is a form of coarse graining? |
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