- #1
kioria
- 54
- 0
Hi,
Given the function:
[tex]P_{k} = \frac{20}{5^{k}}[/tex] for [tex]k \geq 2[/tex]
How would you prove that P is a probability distribution? I would think that you prove that P is bounded by 0 and 1 (i.e., [tex]0 \leq \Sigma P_{k} \geq 1[/tex])
And I guess the leading question is how you would prove that a function is not a probability distribution?
Given the function:
[tex]P_{k} = \frac{20}{5^{k}}[/tex] for [tex]k \geq 2[/tex]
How would you prove that P is a probability distribution? I would think that you prove that P is bounded by 0 and 1 (i.e., [tex]0 \leq \Sigma P_{k} \geq 1[/tex])
And I guess the leading question is how you would prove that a function is not a probability distribution?