Heat transfer equation puzzling results

In summary, the problem involves finding the heat transfer rate of a heated plastic plate in air using the heat transfer equation. The plate is 15cm x 15cm in size and has a temperature difference of 1K. The formula used is Q = k x A x ΔT / d, with k representing the heat conductivity of plastic (0.2 W/(mK)), A representing the area, ΔT representing the temperature difference, and d representing the thickness of the plastic. The result obtained is Q = 2.25W, which is not reasonable compared to the heat transfer rate for a 10K temperature difference. To account for the low conductivity of air, a different value of k (0.024) needs
  • #1
staple
1
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Using heat transfer equation to find out heat transfer rate but reached a puzzling result, where did I do wrong?

Problem statement:
Heat transfer rate of a heated plastic plate in air, considering only one side, the size of the plate is 15cm X 15cm, assuming temperature difference is 1K.

Formula to use:
Q = k × A × ΔT / d

Q: heat transfer rate in Watts
k: heat conductivity of plastic, 0.2 W/(mK)
A: area, 15cm x 15cm
ΔT: temperature difference, 1K
d: thickness of plastic, 2mm

Results:
Pluging in the numbers, Q=2.25W. For 1K temperature diff. the palm size plastic can transfer 2W?

The result is not reasonable. Since for 10K temperature diff. that palm size plastic plate can transfer 22.5W of power. How to include the low conductivity of air into calculation?

Thank you very much for your help.
 
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  • #2
Your value for k, about 0.2 watts per meter per deg. K, is a reasonable value.
Use area = 0.15 meters x 0.15 meters
thickness d = 0.002 meters
ΔT = 1 K
Q = 2.25 watts

Air is very different, and depends on whether there is convection or radiation. This table gives k = 0.024 for air: http://hyperphysics.phy-astr.gsu.edu/hbase/tables/thrcn.html#c1
 

1. What is the heat transfer equation and why is it important in science?

The heat transfer equation is a fundamental equation in thermodynamics that describes how heat is transferred from one system to another. It is important in science because it helps us understand and predict how energy is transferred in various systems, such as heat engines, refrigerators, and industrial processes.

2. Why do some heat transfer equations result in unexpected or puzzling results?

There are a few reasons why this may occur. One reason could be that the assumptions made in the heat transfer equation do not accurately reflect the real-world conditions of the system being studied. Another reason could be that there are external factors, such as convection or radiation, that are not accounted for in the equation.

3. How can I troubleshoot unexpected results in heat transfer equations?

If you are experiencing puzzling results in your heat transfer equation, it is important to carefully review the assumptions and boundary conditions used in the equation. Additionally, you may need to consider external factors and make adjustments to the equation to account for them. It may also be helpful to compare your results with experimental data or simulations to validate your findings.

4. Are there different types of heat transfer equations and when should they be used?

Yes, there are three main types of heat transfer equations: conduction, convection, and radiation. Conduction equations are used for heat transfer through solids, convection equations are used for heat transfer through fluids, and radiation equations are used for heat transfer through electromagnetic waves. The type of equation used depends on the properties of the system being studied and the mode of heat transfer present.

5. How can heat transfer equations be applied in real-world scenarios?

Heat transfer equations have a wide range of applications in various fields, including engineering, physics, and environmental science. They can be used to design and optimize heating and cooling systems, understand the behavior of materials under different temperatures, and predict the effects of climate change. They are also essential in the development of new technologies and innovations.

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