- #1
momogiri
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Question:
Water flows out of a 13.0mm-diameter sink faucet at 2.30m/s.
At what distance below the faucet has the water stream narrowed to 10 mm diameter?
What I've done is that...
I found A_1 (faucet) to be 0.0001327m^2
and A_2 (bottom) to be 0.000314159m^2
So I did the whole A_1*v_1 = A_2*v_2 thing
and found v_2 to be 0.915m/s
Then I plugged it in, into Bernoulli's equation
1/2*rho*v_1^2 + rho*g*y_1 = 1/2*rho*v_2^2 + rho*g*y_2 (cancelling out the P_1 and P_2 because they.. cancel..)
In which it is..
0.5*1000*2.3^2 + 1000*9.8*y_1 = 0.5*1000*0,9715^2 + 1000*9.8*y_2
2645 + 9800*y_1 = 471.906 + 9800*y_2
9800*(y_1 - y_2) = -2174.094
So.. h = 0.222m
Or so I thought... It's wrong, so what am I doing wrong? Is it my A_1 and A_2's, etc.?
Water flows out of a 13.0mm-diameter sink faucet at 2.30m/s.
At what distance below the faucet has the water stream narrowed to 10 mm diameter?
What I've done is that...
I found A_1 (faucet) to be 0.0001327m^2
and A_2 (bottom) to be 0.000314159m^2
So I did the whole A_1*v_1 = A_2*v_2 thing
and found v_2 to be 0.915m/s
Then I plugged it in, into Bernoulli's equation
1/2*rho*v_1^2 + rho*g*y_1 = 1/2*rho*v_2^2 + rho*g*y_2 (cancelling out the P_1 and P_2 because they.. cancel..)
In which it is..
0.5*1000*2.3^2 + 1000*9.8*y_1 = 0.5*1000*0,9715^2 + 1000*9.8*y_2
2645 + 9800*y_1 = 471.906 + 9800*y_2
9800*(y_1 - y_2) = -2174.094
So.. h = 0.222m
Or so I thought... It's wrong, so what am I doing wrong? Is it my A_1 and A_2's, etc.?