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~christina~
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Homework Statement
An amusement park ride consists of a large vertical cylinder that spins about it's axis fast
enough that any person held up against the wall when the floor drops away. The
coeficient of static friction between the person and the wall is [tex]\mu_s[/tex] and the
radius of the cylinder is R.
a) show that the maximum period of relvolution necessary to kep the person from falling is
T= (4 pi^2 R[tex]\mu_s /g) ^1/2[/tex]
b) obtain a numerical value for T, taking R= 4.00m and [tex]\mu_s= 0.400.
[/tex]How many revolutions per minute does the cylinder make?
c) If the rate of revolution of the cylinder is made to be somewhat larger, what happens
to the magnitude of each one of the forces acting on the person?
What happens to the motion of the person?
d) If instead the cylinder's rate of revolution is made to be somewhat smaller, what
happens to the magnitude of each of the forces acting on the person?
What happens in the motion of the person?
picture: http://img337.imageshack.us/img337/3765/19178363wb7.th.jpg
Homework Equations
F= ma= m(v^2/r) ?
The Attempt at a Solution
I have no idea how to explain a person's motion in this ammusement ride according to the forces..
a) I need help in this part
b)
R= 4.00m [tex]\mu_s= 0.400[/tex]
T= (4 pi ^2 R [tex]\mu_s / g)^1/2[/tex]
T= [tex]\sqrt{} (4 pi^2 (4.00m)(0.400) / 9.80m/s^2)[/tex] = 6.44
Revolutions per min? I'm not sure how to get that
I think I'll tackle the the previous before I answer the rest
c)
d)
Help pleaase
Thank You very much
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