- #1
hoser1000
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The question is: Compute the unit-impulse response h[n] for n=0,1,2,3 for each of the following discrete-time systems.
Equation:
y[n+1] + y[n] = 2x[n]
I am trying to figure out how to solve this equation. I understand the example in the book but I don't understand what to do when it calls a future value (n+1)
I rewrote the equation as:
y[n]=2delta[n]-y[n+1]
When n=0 delta[n] is 1 so:
y[0]=2*1-y[1]<-----This is where I am getting confused. Doesn't y[1] refer to my answer when I use the value n=1? How can I get a solution if each equation will refer to the next future equation? The example in the book uses y[n-1] so for each value of n it refers to the previous answer for y[n].
Any help would be much appreciated!
Equation:
y[n+1] + y[n] = 2x[n]
I am trying to figure out how to solve this equation. I understand the example in the book but I don't understand what to do when it calls a future value (n+1)
I rewrote the equation as:
y[n]=2delta[n]-y[n+1]
When n=0 delta[n] is 1 so:
y[0]=2*1-y[1]<-----This is where I am getting confused. Doesn't y[1] refer to my answer when I use the value n=1? How can I get a solution if each equation will refer to the next future equation? The example in the book uses y[n-1] so for each value of n it refers to the previous answer for y[n].
Any help would be much appreciated!