Is this correct (buoyabcy forces - irregular object)?

[alibaba2]

hi, i have an irregular object submerged in water . i would like to verify if I've understood the forces that act on this:
sides A & F - downward force due to weight of water above objects
sides E & D - left nad right force - neutralizing each other
sides B & C - upward buoyancy force

how do sides B & F affect the buoyancy of the object? if it were a regular cube i would understand,
what bothers me is how much downward pressure does the volume of water trapped between B & F exert if side B is 10" and side F is 10.2". the height of the water column between B&F is 1". the distance from A to B is 12".

the depth that the cube is submerged is 30feet.
thanks

 

[stewartcs]

hi, i have an irregular object submerged in water . i would like to verify if I've understood the forces that act on this:
sides A & F - downward force due to weight of water above objects
sides E & D - left nad right force - neutralizing each other
sides B & C - upward buoyancy force

how do sides B & F affect the buoyancy of the object? if it were a regular cube i would understand,
what bothers me is how much downward pressure does the volume of water trapped between B & F exert if side B is 10" and side F is 10.2". the height of the water column between B&F is 1". the distance from A to B is 12".

the depth that the cube is submerged is 30feet.
thanks

The hydrostatic pressure at any point in a fluid is equal to pgh (neglecting atmospheric). Therefore the pressure at B and F will be dependent on their individual heights (h) below the surface of the fluid. B will produce an upward force, and F a downward force.

BTW, you can just calculate the volume of the irregular shaped object and determine the buoyant force instead of using a pressure field approach.

CS

 

[sir-pinski]

Yes, your understanding of the forces acting on the irregular object is correct. Sides A and F experience a downward force due to the weight of water above the object, while sides E and D have equal and opposite forces that cancel each other out. Sides B and C experience an upward buoyancy force due to the displacement of water by the object.

In terms of how sides B and F affect the buoyancy of the object, it depends on the shape and size of the object. If the object is a regular cube, then the buoyancy force would be evenly distributed across all sides. However, for an irregular object, the buoyancy force may be stronger on certain sides depending on their shape and size.

To calculate the downward pressure exerted by the volume of water between sides B and F, you would need to know the density of the water and the dimensions of the object. The pressure would increase with depth, so at 30 feet, the pressure would be greater than at the surface.

I hope this helps clarify your understanding of buoyancy forces on an irregular object in water.