|Nov12-12, 05:46 AM||#1|
Acceleration of a curved trajectory
In paragraph 11-6 he says that the tangent acceleration is the change of speed v but if I look at fig. 11-8 the change in speed is slightly smaller than the change in tangent velocity. (I drew a circle with the radius of the speed of v_I that has it's middle in the origin of the vectors mentally.) I assume he just neglects that difference but I don't really understand the idea of neglecting certain things. What things can you neglect and what not?
He also says that the acceleration at right angles to the curve is the magnitude of the velocity times the change in angle. The magnitude of which velocity? v_I or v_II? How can you just multiply speed with an angle? I know you can if you use sine, cosine or something like that but multiply it with an angle directly?
|Nov12-12, 08:25 AM||#2|
You can neglect things which go to 0 quicker than your relevant effect, if the time-step goes to 0. In other words, everything where effectsize/timestep goes to 0 as timestep goes to 0.
In general, your post looks confusing to me, therefore the very general answer.
|Similar Threads for: Acceleration of a curved trajectory|
|Trajectory and acceleration.||Introductory Physics Homework||11|
|Particle on a curved trajectory||Special & General Relativity||14|
|Lagrangian Mechanics + Constraint: Trajectory of a rolling object on a curved surface||Advanced Physics Homework||1|
|Acceleration from curved spacetime||Special & General Relativity||20|
|Spinning ball bounces off ground, following curved trajectory||Introductory Physics Homework||3|