- #1
lubricarret
- 34
- 0
Homework Statement
Prove that
[1 a b
-a 1 c
-b -c 1]
is invertible for any real numbers a,b,c
Homework Equations
A is invertible if and only if det[A] does not equal 0.
The Attempt at a Solution
I'm not sure if I'm going about this in the correct way;
Would I prove this by solving for the determinant? I did this by cofactor expansion, and came up with:
(1+c^2) - a(-a+bc) + b(ac+b)
= a^2 + b^2 + c^2 + 1
Could I just say then, that the determinant could never be zero, since
a^2 + b^2 + c^2 + 1
will always be nonzero for any real numbers a,b,c?
If someone could just let me know if I did this correctly, or if there is more I need to show.
Thanks!