- #1
swraman
- 167
- 0
Hi,
Im trying to go back and relearn material from a signals class I took to prepare for my controls class.
In the controls class we always deal with CT systems, whereas in the systems class we focused on DT.
My prof derived a frequency response that was H(w) = 1/(1-a*exp(i*w)).
This dint look farmiliar as in my controls class we never have exponentials in the frequency response.
The complex exponential in the Freq response came from y(n) = y(n-1) + x(n), more particularly the y(n-1) part. Now I am guessing the reason this doenst look farmiliar to my controls work is that we always use CT in controls, so there will never be a y(n-1) in our answer. So my question is: What is the CT parallel for the DT term y(n-1)? What makes a CT model have a complex exponential in the solution (aside from actually having y(t) = y(t-1), as y(t-1) doesn't mean the same thing in DT as CT)?
Thanks
Im trying to go back and relearn material from a signals class I took to prepare for my controls class.
In the controls class we always deal with CT systems, whereas in the systems class we focused on DT.
My prof derived a frequency response that was H(w) = 1/(1-a*exp(i*w)).
This dint look farmiliar as in my controls class we never have exponentials in the frequency response.
The complex exponential in the Freq response came from y(n) = y(n-1) + x(n), more particularly the y(n-1) part. Now I am guessing the reason this doenst look farmiliar to my controls work is that we always use CT in controls, so there will never be a y(n-1) in our answer. So my question is: What is the CT parallel for the DT term y(n-1)? What makes a CT model have a complex exponential in the solution (aside from actually having y(t) = y(t-1), as y(t-1) doesn't mean the same thing in DT as CT)?
Thanks