Forces : Man in a lift on a scaler

In summary, the man's weight will be 70 Newton on a static weighing scale, 10 Newton when the lift accelerates down at 10 ms-2, and again 10 Newton when it accelerates up at 10 ms-2.
  • #1
davedays
15
0

Homework Statement


A man of mass 70 kg stands in a lift on a set of weighing scales. The scales are calibrated in Newtons. Assuming that g=10N kg -1
What weight will the scales register when the :

a) lift is static
b)lift accelerates down at 10 ms-2
c)lift accelerates up at 10 ms-2


Homework Equations



F=ma


The Attempt at a Solution



a)
F=ma
F= 70 x 0
F=70

b) accelerates down at 10ms -2

F=ma
F=70 /10
F=7

70-7=63

c) accelerates up at 10 ms -2

70 + 7 = 77

Is this correct ?

Thanks,
dave
 
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  • #2
Can someone please help me ?
 
  • #3
davedays said:
Is this correct ?
No, your answers are not correct. First identify all the forces acting on the man. (One of those forces will equal the scale reading.) Then apply ΣF = ma to each case.

Don't forget to give your answers in Newtons, not kg.
 
  • #4
I don't understand you, sorry. Can you explain again please ?

Is F=ma all I need here ?

I am not sure, however I really want to solve it :)
 
  • #5
davedays said:
I don't understand you, sorry. Can you explain again please ?
What forces act on the man? (Hint: Two forces act on him.) What direction do they act?

Is F=ma all I need here ?
Yes. Realize that F stands for the net force.
 
  • #6
So I think it would be gravity acting down and also the normal force pushing him up, correct ?

Knowing that in the first case I subtract and in the second case I add the forces right ?

However I still do not get the connecting between 'g' and the question. :(
 
  • #7
davedays said:
So I think it would be gravity acting down and also the normal force pushing him up, correct ?
Exactly. And realize that the normal force is what the scale measures.

Knowing that in the first case I subtract and in the second case I add the forces right ?
Just use up as + and down as -. Using that convention, ΣF = N - W.

However I still do not get the connecting between 'g' and the question.
You are given the mass but need the weight (to apply F=ma). That's where 'g' comes in.
 
  • #8
Ill try do a then :

if the GF is pushing him down and NF is pushing him up then his weight is 70N cause the gravity force is greater by 70 N

Second one:
If the lift is going down then the gravity force must he smaller by 10 :

70-10 = 60 N

Third one :

vice versa

70+10=80 N

Am I thinking correct at this time ?

By the way I really appreciate your help and patience here.
 
  • #9
davedays said:
Ill try do a then :

if the GF is pushing him down and NF is pushing him up then his weight is 70N cause the gravity force is greater by 70 N
First things first: If the man's mass is 70 kg, what is the GF on him? (The gravitational force is the same in all three cases, as gravity isn't changing.)
 
  • #10
it must be zero cause he's not going up, right ?
 
  • #11
The man is 70 kg, and there's a gravitational force acting down on him, with this in mind F=m(man)*a(?) even though the elevator isn't accelerating what other acceleration is there?
Keep in mind gravity is in m/s^2.
 
  • #12
davedays said:
it must be zero cause he's not going up, right ?
No. I asked about the gravitational force acting on the man. That's certainly not zero! How do you compute the force of gravity? (That's where you use 'g'.)
 

What is a scaler?

A scaler is a quantity that has only magnitude and no direction. Examples of scalers include temperature, mass, and time.

What are forces?

Forces are interactions between objects that cause a change in their motion. They can be described by their magnitude, direction, and point of application.

How does a man in a lift experience forces?

A man in a lift experiences two main forces: the force of gravity pulling him towards the ground and the normal force from the lift pushing him upwards. If the lift is accelerating, there may also be a force from the lift's motion.

What is the net force on a man in a lift?

The net force on a man in a lift is the vector sum of all the forces acting on him. If the lift is stationary or moving at a constant velocity, the net force will be zero.

How does the weight of the man in a lift change on a scalar?

The weight of the man in a lift will not change on a scalar because weight is a force and therefore has both magnitude and direction. However, the man's mass may be represented as a scaler and will not change, regardless of his location in the lift.

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