Coefficient of Kinetic Friction for crate

In summary, the conversation discusses the attempt to calculate the coefficient of kinetic friction between a crate and a floor, given its weight and the applied force at an angle. The incorrect use of numbers and assumptions about the direction of the applied force are mentioned, and suggestions for solving the problem are given.
  • #1
Tylersaurus
2
0

Homework Statement



A 1500 N crate is being pushed across a level floor at a constant speed by a force F of 700 N at an angle of 20° below the horizontal.

What is the coefficient of kinetic friction between the crate and the floor?

Homework Equations


f=mu(n)

The Attempt at a Solution



I tried 700cos20/1500 + 1500sin20 using the horizontal component of the applied force divided by the normal force, which was mg plus the vertical component of the applied force, but it didn't work, obviously. Any suggestions?
 
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  • #2
Your description seems right, but your numbers don't look right. The vertical component of the applied force is 700sin20... not 1500sin20
 
  • #3
Tylersaurus said:

Homework Statement



A 1500 N crate is being pushed across a level floor at a constant speed by a force F of 700 N at an angle of 20° below the horizontal.

What is the coefficient of kinetic friction between the crate and the floor?

Homework Equations


f=mu(n)


The Attempt at a Solution



I tried 700cos20/1500 + 1500sin20 using the horizontal component of the applied force divided by the normal force, which was mg plus the vertical component of the applied force, but it didn't work, obviously. Any suggestions?
I'm not sure of your equations, but the force is applied below the horizontal; you seem to have assumed when calculating the normal force that the applied force is above the horizontal.
 
  • #4
PhanthomJay said:
I'm not sure of your equations, but the force is applied below the horizontal; you seem to have assumed when calculating the normal force that the applied force is above the horizontal.

no, he assumed it was below the horizontal. He just used 1500 + 1500sin20 for the normal force, instead of 1500 + 700sin20.
 
  • #5
Yeah, I got that later. Thanks, though.
 

What is the coefficient of kinetic friction for a crate?

The coefficient of kinetic friction for a crate refers to the measure of the amount of friction between the crate and the surface it is on when the crate is in motion.

How is the coefficient of kinetic friction for a crate calculated?

The coefficient of kinetic friction for a crate is calculated by dividing the force required to keep the crate in motion by the weight of the crate.

What factors affect the coefficient of kinetic friction for a crate?

The coefficient of kinetic friction for a crate is affected by factors such as the type of surface the crate is on, the weight and material of the crate, and the presence of any lubricants or surface imperfections.

What is a typical range for the coefficient of kinetic friction for a crate?

The coefficient of kinetic friction for a crate can range from 0 to 1, with 0 representing no friction and 1 representing maximum friction. The exact value depends on the specific conditions and materials involved.

How does the coefficient of kinetic friction for a crate impact its movement?

The coefficient of kinetic friction for a crate directly affects its movement by determining the amount of force needed to keep it in motion. A higher coefficient of kinetic friction will require more force to move the crate, while a lower coefficient will result in easier movement.

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