OTHER EDIT!pugfug90 said:I first tried replacing "x" when in parenthese with y. Therefor, 3y+3-y=x, yadda yadda, 2y=x-3, y=(x-3)/2, however, the real answer turned out to be some weird fractional thing. Please give me some kind of direction..
pugfug90 said:3f(3-x)+f(x)=3-x is what I get if I plug in 3-x where x is...
pugfug90 said:Oops haha
So 3f(3-x)+f(x)=(x squared)+9-6x.
So can you tell me where to go from here? I tried substituting y into x again, get (x squared - 6x)/-2, while the real answer is something like x/3+x/5-3 or something. Also, where did the 'plug 3-x for x everywhere' thing came from? And if this is a "topic" I can look up like for quadratic equations, or "f and g compositions"?
He said substitute for, not set equal to.qspeechc said:I am sorry, I was just reading through this thread: how can you substitute x for x-3? Doesn't this imply -3=0?
The equation represents a mathematical relationship between the function f(x) and the variable x, where the sum of 3 times the value of the function at x and the value of the function at 3-x is equal to the square of x.
To solve for f(x), you can use algebraic manipulation to isolate the function on one side of the equation. This may involve factoring, substitution, or other algebraic techniques.
No, there are likely multiple solutions for f(x) that would satisfy this equation. This may depend on the domain and range of the function, and additional information may be needed to determine the specific solution.
Yes, you can use a graph or a table to estimate the value of f(x) for a specific x. However, for a precise solution, it is recommended to use algebraic methods.
Yes, there may be restrictions on the values of x depending on the domain and range of the function and the operations involved in the equation. It is important to consider these restrictions when solving for f(x).