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JackieAnne
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Hi, I am in calculus and am having major struggles. If someone could provide a walk through on how to answer these questions, that would be fantastic. Cheers!
Let f(x)=−3x+6 if x<-3
= 15 if x > -3
Find the average rate of change of f(x) on the interval −5<x<5 .
The average rate of change of f(x) on the interval −5<x<5 is ?
Consider the function f(x)=−7/x+4.
We will take steps to find the tangent line to the graph of f at the point (−7,−3/−7).
(a) Let (xf(x)) be a point on the graph of f with x=−7 . The slope of the (secant) line joining the two points (−7,−3/−7) and (xf(x)) can be simplified to the form A/x+4, where A is a constant. Find A.
Answer: A= .
(b) By considering the slope of the secant line as x approaches −7, find the slope of the tangent line to the graph of f at the point (−7,−3/−7).
Answer: The slope of the tangent line to the graph of f at the point (−7,−3/−7) is .
(c) Find the equation of the tangent line to the graph of f at the point (−7,−3/−7). Write your answer in the form y=mx+b.
Let f(x)=−3x+6 if x<-3
= 15 if x > -3
Find the average rate of change of f(x) on the interval −5<x<5 .
The average rate of change of f(x) on the interval −5<x<5 is ?
Consider the function f(x)=−7/x+4.
We will take steps to find the tangent line to the graph of f at the point (−7,−3/−7).
(a) Let (xf(x)) be a point on the graph of f with x=−7 . The slope of the (secant) line joining the two points (−7,−3/−7) and (xf(x)) can be simplified to the form A/x+4, where A is a constant. Find A.
Answer: A= .
(b) By considering the slope of the secant line as x approaches −7, find the slope of the tangent line to the graph of f at the point (−7,−3/−7).
Answer: The slope of the tangent line to the graph of f at the point (−7,−3/−7) is .
(c) Find the equation of the tangent line to the graph of f at the point (−7,−3/−7). Write your answer in the form y=mx+b.
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