- #1
Physics-Pure
- 29
- 0
Hello all~
Given the equation:
dy/dx = (x/y)
I know we would initially go to:
∫dy =∫ (x/y) dx
then too:
∫(y)(dy) = ∫x dx
Until arriving at:
(y2/2) + C1 = (x2/2) + C2
(y2) - (x2) = C
My question is:
Where does the dy disappear to in step 4? Where the anti-derivative is taken.
Why does ∫dy become just y when solving an equation of the form
dy/dx = (x2 + 1), but it disappears in the first example?
Thank you~
Given the equation:
dy/dx = (x/y)
I know we would initially go to:
∫dy =∫ (x/y) dx
then too:
∫(y)(dy) = ∫x dx
Until arriving at:
(y2/2) + C1 = (x2/2) + C2
(y2) - (x2) = C
My question is:
Where does the dy disappear to in step 4? Where the anti-derivative is taken.
Why does ∫dy become just y when solving an equation of the form
dy/dx = (x2 + 1), but it disappears in the first example?
Thank you~