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I have 2 questions.
1)what is the remainder with 100! is divided by 103? explain your answer
2)a = 238000 = 2^4 x 5^3 x 7 x 17 and b=299880 = 2^3 x 3^2 x 5 7^2 17. Is there an integer so that a divides b^n? if so what is the smallest possibility for n?
the first one i have no idea how to even start it and the second one i know that the prime factorization helps to find out what n is.
1)what is the remainder with 100! is divided by 103? explain your answer
2)a = 238000 = 2^4 x 5^3 x 7 x 17 and b=299880 = 2^3 x 3^2 x 5 7^2 17. Is there an integer so that a divides b^n? if so what is the smallest possibility for n?
the first one i have no idea how to even start it and the second one i know that the prime factorization helps to find out what n is.